Category: Class 7

Students can Download Maths Chapter 1 Number System Ex 1.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2

Question 1.
Fill in the following place value table.

Answer:

Question 2.
Write the decimal numbers from the following place value table.

Answer:

Question 3.
Write the following decimal numbers in the place value table.
(i) 25.178
(ii) 0.025
(iii) 428.001
(iv) 173.178
(v) 19.54
Solution:
(i) 25.178

(ii) 0.025

(iii) 428.001

(iv) 173.178

(v) 19.54

Question 4.
Write each of the following as decimal numbers.
(i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \)
(ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \)
(iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \)
(iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \)
(v) \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 1 }{ 1000 } \)
Solution:
(i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \) = 21 + 2 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) + 7 × \(\frac { 1 }{ 1000 } \) = 21.237

(ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) = 3 + 8 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) + 5 × \(\frac { 1 }{ 1000 } \) = 3.845

(iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 6 + 0 × \(\frac { 1 }{ 10 } \) + 0 × \(\frac { 1 }{ 100 } \) + 9 × \(\frac { 1 }{ 1000 } \) = 6.009

(iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \) = 956 + 0 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 956.03

(v) \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 1 }{ 1000 } \) = 6 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 0.631

Question 5.
Convert the following fractions into decimal numbers.
(i) \(\frac { 3 }{ 10 } \)
(ii) 3 \(\frac { 1 }{ 2 } \)
(iii) 3 \(\frac { 3 }{ 5 } \)
(iv) \(\frac { 3 }{ 2 } \)
(v) \(\frac { 4 }{ 5 } \)
(vi) \(\frac { 99 }{ 100 } \)
(vii) 3 \(\frac { 19 }{ 25 } \)
Solution:
(i) \(\frac { 3 }{ 10 } \) = 0.3
(ii) 3 \(\frac { 1 }{ 2 } \) = \(\frac { 7 }{ 2 } \) = \(\frac{7 \times 5}{2 \times 5}\) = \(\frac { 35 }{ 10 } \) = 3.5
(iii) 3 \(\frac { 3 }{ 5 } \) = \(\frac { 18 }{ 5 } \) = \(\frac{18 \times 2}{5 \times 2}\) = \(\frac { 36 }{ 10 } \) = 3.6
(iv) \(\frac { 3 }{ 2 } \) = \(\frac{3 \times 5}{2 \times 5}\) = \(\frac { 15 }{ 10 } \) = 1.5
(v) \(\frac { 4 }{ 5 } \) = \(\frac{4 \times 2}{5 \times 2}\) = \(\frac { 8 }{ 10 } \) = 0.8
(vi) \(\frac { 99 }{ 100 } \) = 0.99
(vii) 3 \(\frac { 19 }{ 25 } \) = \(\frac { 94 }{ 25 } \) = \(\frac{94 \times 4}{25 \times 4}\) = \(\frac { 376 }{ 100 } \) = 3.76

Question 6.
Write the following decimals as fractions.
(i) 2.5
(ii) 6.4
(iii) 0.75
Solution:
(i) 2.5 = 2 + \(\frac { 5 }{ 10 } \) = \(\frac { 25 }{ 10 } \)
(ii) 6.4 = 6 + \(\frac { 4 }{ 10 } \) = \(\frac { 64 }{ 10 } \)
(iii) 0.75 = 0 + \(\frac { 7 }{ 10 } \) + \(\frac { 5 }{ 100 } \) = \(\frac { 70+5 }{ 100 } \) = \(\frac { 75 }{ 100 } \)

Question 7.
Express the following decimals as fractions in lowest form.
(i) 2.34
(ii) 0.18
(iii) 3.56
Solution:
(i) 2.34 = 2 + \(\frac { 34 }{ 100 } \) = 2 + \(\frac{34 \div 2}{100 \div 2}\) = 2 + \(\frac { 17 }{ 50 } \) = 2\(\frac { 17 }{ 50 } \) = \(\frac { 117 }{ 50 } \)
(ii) 0.18 = 0 + \(\frac { 18 }{ 100 } \) = \(\frac{18 \div 2}{100 \div 2}\) = \(\frac { 9 }{ 50 } \)
(iii) 3.56 = 3 + \(\frac { 56 }{ 100 } \) = 3 + \(\frac{56 \div 4}{100 \div 4}\) = 3 + \(\frac { 14 }{ 25 } \) = 3 \(\frac { 14 }{ 25 } \) = \(\frac { 89 }{ 25 } \)

Objective Questions

Question 8.
3 + \(\frac { 4 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = ?
(i) 30.49
(ii) 3049 9
(iii) 3.0049
(iv) 3.049
Answer:
(iv) 3.049
Hint: = 3 × 1 + \(\frac { 0 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 3.049

Question 9.
\(\frac { 3 }{ 5 } \) = _______
(i) 0.06
(ii) 0.006
(iii) 6
(iv) 0.6
Answer:
(iv) 0.6
Hint: \(\frac { 3 }{ 5 } \) = \(\frac{3 \times 2}{5 \times 2}\) = \(\frac { 6 }{ 10 } \) = 0.06

Question 10.
The simplest form of 0.35 is
(i) \(\frac { 35 }{ 1000 } \)
(ii) \(\frac { 35 }{ 10 } \)
(iii) \(\frac { 7 }{ 20 } \)
(iv) \(\frac { 7 }{ 100 } \)
Answer:
(iii) \(\frac { 7 }{ 20 } \)
Hint: 0.35 = \(\frac { 35 }{ 100 } \) = \(\frac{35 \div 5}{100 \div 5}\) = \(\frac { 7 }{ 20 } \)

Students can Download Maths Chapter 1 Number System Ex 1.4 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4

Question 1.
Write the decimal numbers represented by the points P, Q, R and S on the given number line.

Solution:
The unit length between 1 and 2 is divided into 10 equal parts and the third part is taken as Q.
∴ Q represents 1 + 0.3 = 1.3
The unit lenth between 3 and 4 is divided into 10 equal parts and the 6th part is taken as P.
∴ P represents 3 + 0.6 = 3.6
The unit length between 4 and 5 is divied into 10 equal parts and the second part is taken as S.
∴ S represents 4 + 0.2 = 4.2
The unit length between 6 and 7 is divided into 10 equal parts and the 8th part is taken.
∴ R represents 6 + 0.8 = 6.8
P(3.6), Q(1.3), R(6.8), S(4.2).

Question 2.
Represent the following decimal numbers on the number line.
(i) 1.7
(ii) 0.3
(iii) 2.1
Solution:
(i) 1.7
We know that 1.7 is more than 1, but less than 2.
There are one ones and 7 tenths in it. Divide the unit length between 1 and 2 on the number line into 10 equal parts and take 7 parts which represents 1.7 = 1 + 0.7

(ii) 0.3
We know that 0.3 is more than 0, but less than 1.
There are 3 tenths in it. Divide the unit lenght between 0 and 1 on the number line into 10 equal parts and take 3 parts, which represent 0.3.

(iii) 2.1
We knowthat 2.1 is more than 2 and less than 3.
There are 2 ones and 1 tenths in it.
Divide the unit length between 2 and 3 into 10 equal parts and take 1 part, which represemt 2.1 = 2 + 0.1

Question 3.
Between which two whole numbers, the following decimal numbers lie?
(i) 3.3
(ii) 2.5
(iii) 0.9
Solution:
(i) 3.3 – 3.3 lies between 3 and 4.
(ii) 2.5 – 2.5 lies between 2 and 3.
(iii) 0.9 – 0.9 lies between 0 and 1.

Question 4.
Find the greater decimal number in the following.
(i) 2.3,3.2
(ii) 5.6,6.5
(iii) 1.2,2.1
Solution:
(i) 2.3, 3.2
Comparing the whole number parts of 2.3 and 3.2 we get 3 > 2.
3.2 > 2.3 – Greater number is 3.2

(ii) 5.6, 6.5
Comparing the whole number parts of 5.6 and 6.5, we get 6 > 5.
6.5 > 5.6 – Greater number is 6.5

(iii) 1.2, 2.1
Comparing the whole number parts of 1.2 and 2.1, we get 2 > 1.
2.1 > 1.2 – Greater number is 2.1

Question 5.
Find the smaller decimal number in the following.
(i) 25.3,25.03
(ii) 7.01,7.3
(iii) 5.6,6.05
Solution:
(i) 25.3, 25.03
The whole number parts of both the numbers are equal.
∴ Comparing the digits at tenths place we get 0 < 3.
∴ 25.03 < 25.3 – Smaller number 25.03

(ii) 7.01,7.3
The whole number parts of both the numbers are equal.
Comparing the digits at tenths place we get 0 < 3.
∴ 7.01 < 7.3 – Smaller number is 7.01.

(iii) 5.6, 6.05
Comparing the whole number parts, we get 5 < 6.
∴ 5.6 < 6.05 – Smaller number is 5.6

Objective Question

Question 6.
Between which two whole numbers 1.7 lie?
(i) 2 and 3
(ii) 3 and 4
(iii) 1 and 2
Answer:
(iii) 1 and 2

Question 7.
The decimal number which lies between 4 and 5 is _______
(i) 4.5
(ii) 2.9
(iii) 1.9
Answer:
(i) 4.5

You can Download Samacheer Kalvi 7th Science Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Science Solutions Term 2 Chapter 6 Digital Painting

Samacheer Kalvi 7th Science Digital Painting Textual Evaluation

I. Choose the correct answer:

Question 1.
Tux paint software is used to
(a) Paint
(b) Program
(c) Scan
(d) PDF
Answer:
(a) Paint

Question 2.
Which toolbar is used for drawing and editing controls in tux paint software?
(a) Left Side: Toolbar
(b) Right side : Toolbar
(c) Middle : Tool bar
(d) Bottom : Tool bar
Answer:
(a) Left Side: Toolbar

Question 3.
What is the shortcut key for undo option?
(a) Ctrl + Z
(b) Ctrl + R
(c) Ctrl + Y
(d) Ctrl+N
Answer:
(a) Ctrl + Z

Question 4.
Tux Math software helps in learning the
(a) Painting
(b) Arithmetic
(c) Programming
(d) Graphics
Answer:
(b) Arithmetic

Question 5.
In Tux Math, Space cadet option is used for
(a) Simple addition
(b) Division
(c) Drawing
(d) Multiplication
Answer:
(a) Simple addition

II. Answer the following Questions:

Question 1.
What is Tux Paint ?
Answer:
Tux Paint is a free drawing program designed for young children.

Question 2.
What is the use of Text Tool ?
Answer:
Text tool is used to type texts.

Question 3.
What is the Shortcut key for Save option?
Answer:
Ctrl + S

Question 4.
What is Tux Math?
Answer:
Tux Math is an open source arcade – style video game for learning arithmetic.

Question 5.
What is the use of Ranger?
Answer:
Ranger is used to do addition, subtraction, multiplication and division to ten.

Samacheer Kalvi 7th Science Digital Painting Additional Questions

I. Choose the correct answer.

Question 1.
Which tool is used to open an existing file
(a) Line
(b) Open
(c) New
(d) Undo
Answer:
(b) Open

Question 2.
What is the shortcut key for printing option?
(a) Ctrl + S
(b) Ctrl + O
(c) Ctrl + P
(d) Ctrl + Y
Answer:
(c) Ctrl + P

Question 3.
In tux paint scout option is used for
(a) Simple addition
(b) Addition and subtraction to ten
(c) Division
(d) Multiplication
Answer:
(b) Addition and subtraction to ten

Question 4.
Which tool is used to cancel a command given earlier.
(a) Quit
(b) magic
(c) eraser
(d) undo
Answer:
(d) undo

Question 5.
Which tool is like a rubber stamps or stickers
(a) text
(b) stamp
(c) eraser
(d) magic
Answer:
(b) stamp

II.Fill in the Blanks

1. When Tux paint first loads, a ________ screen will appear.
2. The ________ tool helps us to draw freehand drawings.
3. The ________ tool is used to draw lines.
4. The ________ tool has a set of special tools.
5. Clicking the ________ button will start a new drawing.

Answer:

1. title / credits
2. paint brush
3. line
4. Magic
5. New

III. Question and answers:

Question 1.
What is the use of shapes tool?
Answer:
Shape tool is used to draw some simple filled and un-filled shapes.

Question 2.
What is play Arcade Game?
Answer:
This option is used to select and play one of the four open ended “arcade style”games.

Question 3.
Which tool is used to closed Tux Paint window?
Answer:
Quit tool is used to close Tux Paint window.

Question 4.
What is the use of selector?
Answer:
Selector display the options associated with the specific tool.

Question 5.
What is help area?
Answer:
Help area is in the bottom of the screen. It provides tips and other information while you draw.

Question 6.
What is magic tool?
Answer:
Magic tool is a set of special tools, selecting one of the ‘magic’ effects from the selector situated in the right side. This tool provides countless number of special visual effects if it is used in various combination with other tools.

IV. Give Long answers:

Question 1.
What are the short keys in computers?
Answer:

Tool Name	Key board Short Key
New	Ctrl+N
Open	Ctrl+O
Save	Ctrl+S
Print	Ctrl+P
Quit	Esc
Undo	Ctrl+Z
Redo	Ctrl+Y

Students can Download Maths Chapter 1 Number System Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Additional Questions

Additional Questions and Answers

Exercise 1.1

Question 1.
Express as rupees using decimals.
(i) 4 paise
(ii) 4 rupees 4 paise
(iii) 44 rupees 44 paise
(iv) 50 paise
(v) 625 paise
Solution:
We know that 100 paise = ₹ 1
1 paise = ₹ \(\frac { 1 }{ 100 } \)
(i) 4 paise = ₹ 4 × \(\frac { 1 }{ 100 } \) = ₹ \(\frac { 4 }{ 100 } \) = ₹ 0.04
(ii) 4 rupees 4 paise = ₹ 4 + ₹ 0.04 = ₹ 4.04
(iii) 44 rupees 4 paise = ₹ 44 + 44 paise = ₹ 44 + ₹ \(\frac { 44 }{ 100 } \) = ₹ 44 + ₹ 0.44 = ₹ 44.44
(iv) 625 paise = 600 paise + 25 paise = ₹ 6 + ₹ \(\frac { 25 }{ 100 } \) = ₹ 6 + ₹ 0.25 = ₹ 6.25

Question 2.
Express 7 cm in metre and kilometer.
Solution:
7 cm = \(\frac { 7 }{ 100 } \) m = 0.07 m
7 cm = \(\frac { 7 }{ 10000 } \) km = 0.00007 km

Question 3.
Write the following decimal numbers in the expanded form.
(i) 30.04
(ii) 3.04
(iii) 300.04
Solution:
(i) 30.04 = 3 × 10 + 0 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) = 3 × 10 + \(\frac { 4 }{ 100 } \)
(ii) 3.04 = 3 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) = 3 × 1 + \(\frac { 4 }{ 100 } \)
(iii) 300.04 = 3 × 100 + 0 × 10 + 0 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) = 3 × 100 + \(\frac { 4 }{ 100 } \) = 3 × 100 + \(\frac { 4 }{ 100 } \)

Question 4.
Write the place value of 2 in the following decimal numbers.
(i) 2.47
(ii) 26.89
(iii) 36.28
Solution:
(i) 2.47 Place value of 2 in 2.47 is ones.
(ii) 26.89 Place value of 2 in 26.89 is Tens.
(iii) 36.28 Place value of 2 in 36.28 is tenths

Exercise 1.2

Question 1.
Explain the following as fractions.
(i) Ajar containing 3.6 litres of milk.
(ii) A cup containing 9.63 mg of medicine.
Solution:
(i) 3.6 = 3 + \(\frac { 6 }{ 10 } \) = 3 + \(\frac { 3 }{ 5 } \) = 3 \(\frac { 3 }{ 5 } \) litre of milk
(ii) 9.63 = 9 + \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) = \(\frac { 900+60+3 }{ 100 } \) = \(\frac { 963 }{ 100 } \) mg of medicine

Question 2.
Convert into decimal.
(i) Three hundred three and nine hundredths.
(ii) Six and fifty five thousands
Solution:
(i) Three hundred three and nine hundredths
= 303 + \(\frac { 9 }{ 100 } \) = 303 + 0 × \(\frac { 1 }{ 10 } \) + 9 × \(\frac { 1 }{ 100 } \) = 303.09

(ii) Six and fifty five thousands
6 + \(\frac { 55 }{ 100 } \) = 6 + \(\frac { 5 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) = 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 5 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) = 6.055

Question 3.
Find the decimal form of (i) 194 + 20 + 3 + \(\frac { 7 }{ 10 } \) + \(\frac { 2 }{ 100 } \)
(ii) 111 + 11 + 1 + \(\frac { 1 }{ 10 } \) + \(\frac { 1 }{ 1000 } \)
Solution:
(i) 194 + 20 + 3 + \(\frac { 7 }{ 10 } \) + \(\frac { 2 }{ 100 } \) = 217 + 7 × \(\frac { 1 }{ 10 } \) + 2 × \(\frac { 1 }{ 100 } \) = 217.72

(ii) 111 + 11 + 1 + \(\frac { 1 }{ 10 } \) + \(\frac { 1 }{ 1000 } \) = 123 + 1 × \(\frac { 1 }{ 10 } \) + 0 × \(\frac { 1 }{ 100 } \) + 1 × \(\frac { 1 }{ 1000 } \) = 123.101

Exercise 1.3

Question 1.
Maya bought 5 kg 300 g bananas and 3 kg 250 kg oranges. Diya bought 4 kg 800 g apples and 4 kg 150 g of mangoes. Who bought more fruits.
Solution:
Total fruits bought by Maya = 5 kg 300 g + 3 kg 250 g = 8 kg 550 g = 8.550 kg
Total fruits Diya bought = 4 kg 800 g + 4 kg 150 g = 8 kg 950 g = 8.950 kg
Comparing the whole number parts, they are equal.
Comparing thet tenths place we get 9 > 5.
∴ 8.950 kg > 8.550 kg
∴ Diya bought more fruits.

Question 2.
Which is greater 28 km or 42.6 km.
Solution:
Comparing the whole number part 42 > 28.
42.6 km is greater than 28 km.

Exercise 1.4

Question 1.
Show that the following numbers in a number line.
(i) 0.2
(ii) 1.8
(iii) 1.1
(iv) 2.6
Solution:

Question 2.
Write the decimal numbers represented by the points A, B, C, D, E and F.
Solution:

A (0.5); B (1.2); C (2.3); D (2.8); E (3.4); F (3.9)

Students can Download Maths Chapter 1 Number System Ex 1.5 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Question 1.
Write the following decimal numbers in the place value table.
(i) 247.36
(ii) 132.105
Solution:
(i) 247.36

(ii) 132.105

Question 2.
Write each of the following as decimal number.
(i) 300 + 5 + \(\frac { 7 }{ 10 } \) + \(\frac { 9 }{ 100 } \) + \(\frac { 2 }{ 100 } \)
(ii) 1000 + 400 + 30 + 2 + \(\frac { 6 }{ 10 } \) + \(\frac { 7 }{ 100 } \)
Solution:
(i) 300 + 5 + \(\frac { 7 }{ 10 } \) + \(\frac { 9 }{ 100 } \) + \(\frac { 2 }{ 100 } \) = 305.792
(ii) 1000 + 400 + 30 + 2 + \(\frac { 6 }{ 10 } \) + \(\frac { 7 }{ 100 } \) = 1432.67

Question 3.
Which is greater?
(i) 0.888 (or) 0.28
(ii) 23.914 (or) 23.915
Solution:
(i) 0.888 (or) 0.28
The whole number parts is equal for both the numbers.
Comparing the digits in the tenths place we get, 8 > 2.
0.888 > 0.28 ∴ 0.888 is greater.

(ii) 23.914 or 23.915
The whole number part is equal in both the numbers.
Also the tenth place and hundredths place are also equal.
∴ Comparing the thousandths place, we get 5 > 4.
23.915 > 23.914 ∴ 23.915 is greater.

Question 4.
In a 25 m swimming competition, the time taken by 5 swimmers A, B, C, D and E are 15.7 seconds, 15.68 seconds, 15.6 seconds, 15.74 seconds and 15.67 seconds respectively. Identify the winner.
Solution:
The winner is one who took less time for swimming 25 m.
Comparing the time taken by A, B, C, D, E the whole number part is equal for all participants.
Comparing digit in tenths place we get 6 < 7.
∴ Comparing 15.68, 15.6, 15.67, that is comparing the digits in hundredths place we get 15.60 < 15.67 < 15.68
One who took 15.6 seconds is the winner. ∴ C is the winner.

Question 5.
Convert the following decimal numbers into fractions
(i) 23.4
(ii) 46.301
Solution:
(i) 23.4 = \(\frac { 234 }{ 10 } \) = \(\frac{234 \div 2}{10 \div 2}\) = \(\frac { 117 }{ 5 } \)
(ii) 46.301 = \(\frac { 46301 }{ 1000 } \)

Question 6.
Express the following in kilometres using decimals,
(i) 256 m
(ii) 4567 m
Solution:
1 m = \(\frac { 1 }{ 1000 } \) km = 0.001 Km
(i) 256 m = \(\frac { 256 }{ 1000 } \) km = 0.256 km
(ii) 4567 m = \(\frac { 4567 }{ 1000 } \) km = 4.567 km

Question 7.
There are 26 boys and 24 girls in a class. Express the fractions of boys and girls as decimal numbers.
Solution:
Boys = 26; Girls = 24; Total = 50
Fraction of boys = \(\frac { 26 }{ 50 } \) = \(\frac{26 \times 2}{50 \times 2}\) = \(\frac { 52 }{ 100 } \) = 0.52
Fraction of girls = \(\frac { 24 }{ 50 } \) = \(\frac{24 \times 2}{50 \times 2}\) = \(\frac { 48 }{ 100 } \) = 0.48

Challenge Problems

Question 8.
Write the following amount using decimals.
(i) 809 rupees 99 paise
(ii) 147 rupees 70 paise
Solution:
100 paise = 1 rupee; 1 paise = \(\frac { 1 }{ 100 } \) rupee

(i) 809 rupees 99 paise = 809 rupees + \(\frac { 99 }{ 100 } \) rupees
= 809 + 0.99 rupees = ₹ 809.99

(ii) 147 rupees 70 paise = 147 rupees + \(\frac { 70 }{ 100 } \) rupees
= 147 rupees + 0.70 rupees = ₹ 147.70

Question 9.
Express the following in metres using decimals.
(i) 1328 cm
(ii) 419 cm
Solution:
100 cm = 1 m; 1 cm = \(\frac { 1 }{ 100 } \) m
(i) 1328 cm = \(\frac { 1328 }{ 100 } \) m = 13.28 m
(ii) 419 cm = \(\frac { 419 }{ 100 } \) m = 4.19 m

Question 10.
Express the following using decimal notation.
(i) 8 m 30 cm in metres
(ii) 24 km 200 m in kilometres
Solution:
(i) 8 m 30 cm in metres
8 m + \(\frac { 30 }{ 100 } \) m = 8 m + 0.30 m = 8.30 m

(ii) 24 km 200 m in kilometres
24 km + \(\frac { 200 }{ 1000 } \) km = 24 km + 0.200 km = 24.200 km

Question 11.
Write the following fractions as decimal numbers.
(i) \(\frac { 23 }{ 10000 } \)
(ii) \(\frac { 421 }{ 100 } \)
(iii) \(\frac { 37 }{ 10 } \)
Solution:
(i) \(\frac { 23 }{ 10000 } \) = 0.0023
(ii) \(\frac { 421 }{ 100 } \) = 4.21
(iii) \(\frac { 37 }{ 10 } \) = 3.7

Question 12.
Convert the following decimals into fractions and reduce them to the lowest form,
(i) 2.125
(ii) 0.0005
Solution:
(i) 2.125 = \(\frac { 2125 }{ 1000 } \) = \(\frac{2125 \div 25}{1000 \div 25}\) = \(\frac { 85 }{ 40 } \) = \(\frac{85 \div 5}{40 \div 5}\) = \(\frac { 17 }{ 8 } \)

(ii) 0.0005 = \(\frac { 5 }{ 1000 } \) = \(\frac{5 \div 5}{10000 \div 5}\) = \(\frac { 1 }{ 2000 } \)

Question 13.
Represent the decimal numbers 0.07 and 0.7 on a number line.
Solution:

0.07 lies between 0.0 and 0.1
The unit space between 0 and 0.1 is divided into 10 equal parts and 7th part is taken. Also 0.7 lies between 0 and 1.
The unit space between 0 and 1 is divided into 10 equal parts, and the 7th part is taken.

Question 14.
Write the following decimal numbers in words.
(i) 4.9
(ii) 220.0
(iii) 0.7
(iv) 86.3
Solution:
(i) 4.9 = Four and nine tenths
(ii) 220.0 = Two hundred and twenty
(iii) 0.7 = Seven tenths
(iv) 86.3 = Eighty six and three tenths.

Question 15.
Between which two whole numbers the given numbers lie?
(i) 0.2
(ii) 3.4
(iii) 3.9
(iv) 2.7
(v) 1.7
(vi) 1.3
Solution:
(i) 0.2 lies between 0 and 1.
(ii) 3.4 lies between 3 and 4.
(iii) 3.9 lies between 3 and 4.
(iv) 2.7 lies between 2 and 3.
(v) 1.7 lies between 1 and 2.
(vi) 1.3 lies between 1 and 2.

Question 16.
By how much is \(\frac { 9 }{ 10 } \) km less than 1 km. Express the same in decimal form.
Solution:
Given measures are 1 km and \(\frac { 9 }{ 10 } \) km. i.e., 1 km and 0.9 km.
Difference = 1.0 – 0.9 = 0.1 km.

Students can Download Maths Chapter 5 Information Processing Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 5 Information Processing Additional Questions

Additional Questions and Answers

Exercise 5.1

Question 1.
Find the relationship between x and y if

Solution:
The relationship between x and y is y = -5x

Question 2.
Find the relationship between x and y if

Solution:
The relationship between x andy is y = 3x + 2

Exercise 5.2

Question 1.
Find the sum of the elements of Pascal’s triangle and find the relationship between the numbers obtained.
Solution:
Pascal’s triangle with sum of elements is given by

The numbers formed are 1, 2, 4, 8, 16, 32, 64, …………..
They can be written as 2⁰, 2¹, 2², 2³, 2⁴, 2⁵, 2⁶, …………..
So they are the powers of base 2
The relationship is given by 2^x-1 if x represents the row.

Exercise 5.3

Question 1.
If the following numbers are taken from Pascal’s triangle find the missing numbers.

1. 9, 1, _____ = 45, 1, 11
2. 1, 6, _____ = 1, 4, 15
3. 21, 8, 1 = _____, 6, 28

Solutions:

1. 55
2. 10
3. 1

Students can Download Maths Chapter 5 Information Processing Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 5 Information Processing Intext Questions

Activity (Text book Page No. 91)

Question 1.
Observe the pattern given below. Continue the pattern for three more steps.

Let, ‘x’ be the number of steps and ‘y’ be the number of match sticks. Tabulate the values of ‘x’ and ‘y’ and verify the relationship y = 7x + 5.
Solution:
Three more patterns are

From the table y = 7x + 5 is verified.

Try These (Text book Page No. 92)

Question 1.
In the given figure, let Y denote the number of steps and y denote its area. Find the relationship between x and y by tabulation.

Solution:
Let x denote the number of steps and y denote the area.
In the first shape let x = 1 and the area be 1 cm²
when x = 2 : Area = 22 = 4 cm²
whenx = 3 : Area = 32 = 9 cm² and so on.
Tabulating the values of x and y

From the table:
x = 1 ⇒ y = 1²
x = 2 ⇒ y = 2²
x = 4 ⇒ y = 4²
x = 5 ⇒ y = 5²
Hence the relationship between x and y is y = x²

Question 2.
In the figure, let x denotes the number of steps and y denotes the number of matchsticks used. Find the relationship between Y and y by tabulation.

Solution:
Let x denote the number of steps and y denote the number of matchsticks used.
In step 1, x = 1 ⇒ y = number of mathsticks used is 1
In step 2, x = 2 ⇒ y = number of mathsticks used is 4
In step 3, x = 3 ⇒ y = number of mathsticks used is 7 and so on.
The values of v andy are tabulated as

x = 1 ⇒ y = 1 = 3(1) – 2
x = 2 ⇒ y = 4 = 3(2) – 2
x = 3 ⇒ y = 7 = 3(3) – 2
x = 4 ⇒ y = 10 = 3(4) – 2
From the table y = 3x – 2

Question 3.
Observe the table given below.

Find the relationship between x and y. What will be the value of y, when x = 8.
Solution:
Soil When x = – 2 y = 2 (-2) = -4
When x = -1 y = 2 (-1) = -2
When x = 0 y = 2 (0) = 0
When x =1 y = 2(1) = 2
When x = 2 y = 2 (2) = 4
When x = 8 y = 2 (8) = 16.
Also y = 2x is the relation between x and y.

Activity (Text book Page No. 93 & 94)

Question 1.
Complete the following Pascal’s Triangle by observing the number pattern.

Solution:
Pascal’s triangle is given by

Question 2.
Observe the above completed and r find the sequence that you see in it and complete them.

(i) 1,2, 3, 4, 5, 6, 7.
(ii) 1, 3, _____, _____, _____, _____.
(iii) 1, _____, _____, _____, _____,
(iv) _____, _____, _____, _____.
Solution:
(i) 1,2, 3, 4, 5, 6, 7.
(ii) 1,3,6,10,15,21.
(iii) 1,4,10,20,35.
(iv) 1,5,15,35.

Question 3.
Observe the sequence of numbers obtained in the 3rd and 4th slanting rows of Pascal’s Triangle and find the difference between the consecutive numbers and complete the table given below.

Solution:

Try These (Text book Page No. 96)

Question 1.
Observe the pattern of numbers given in the slanting rows earlier and complete the Pascal’s Triangle.

Solution:

Question 2.
Complete the given Pascal’s Triangle. Find the common property of the numbers filled by you. Can you relate this pattern with the pattern discussed in situation 2. Discuss.

Solution:

Common Properties:
The numbers filled by me are even numbers. Also they make triangular shape.
Yes, this pattern and the pattern given in situation 2 have the same properties.

Students can Download Maths Chapter 5 Information Processing Ex 5.3 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 5 Information Processing Ex 5.3

Miscellaneous Practice Problems

Question 1.
Choose the correct relationship between x and y for the given table.

(i) y = x + 4
(ii) y = x + 5
(iii) y = x + 6
(iv) y = x + 7
Answer:
(iii) y = x + 6

Question 2.
Find the triangular numbers from the Pascal’s Triangle and colour them.

Solution:
Triangular numbers are numbers the objects of which can be arranged in the form of equilateral triangle.
Example : 1, 3, 6, 10, 15,…
From Pascal’s Triangle, the triangular numbers are

Question 3.
Write the first five numbers in the third slanting row of the Pascal’s Triangle and find their squares. What do you infer?
Solution:

Numbers in the 3rd slanding row are 1, 3, 6, 10, 15, 21,….
The squares are 1², 3², 6², 10². 15², 21²,…. = 1, 9, 36, 100, 225, 441,…

From the above table we can conclude that the squares of the triangular numbers are the sum of cubes of natural numbers.

Challenge Problems

Question 4.
Tabulate and find the relationship between the variables (x and y) for the following patterns.

Solution:
(i) Let the number of steps be x and the number of shapes be y.
Tabulating the values of x and y

From the table
x = 1 ⇒ y = 1 = 12
x = 2 ⇒ y = 4 = 22
x = 3 ⇒ y = 9 = 32
x = 4 ⇒ y = 16 = 42
Hence the relationship between x and y is y = x2.

(ii) Let the number of steps be x and the number of shapes be y.
Tabulating the values of x and y

From the table x = 1 ⇒ y = 1 = 1
x = 2 ⇒ y = 2 + 1 = 3
x = 3 ⇒ y = 3 + 2 = 5
x = 4 ⇒ y = 4 + 3 = 7
x = 5 ⇒ y = 5 + 4 = 9
Hence the relationship between x and y is y = 2x-1.

Question 5.
Verify whether the following hexogonal shapes form a part of the Pascal’s Triangle.

Solution:
In Pascal’s Triangle product of the 3 alternate numbers given around the hexagon is equal to the product of remaining three numbers.

1 × 13 × 66 = 11 × 1 × 78 = 858
∴ It form a part of Pascal’s Triangle.

5 × 21 × 20 = 10 × 6 × 35 = 2100
∴ It form a part of Pascal’s Triangle

8 × 45 × 84 = 28 × 9 × 120 = 30240
∴ It form a part of Pascal’s Triangle

56 × 210 × 126 = 70 × 84 × 252 = 1481760
∴ It form a part of Pascal’s Triangle

Students can Download Maths Chapter 5 Information Processing Ex 5.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 5 Information Processing Ex 5.2

Question 1.
Complete the Pascal’s Triangle.

Solution:

Question 2.
The following hexagonal shapes are taken from Pascal’s Triangle. Fill in the missing numbers.

Solution:

Question 3.
Complete the Pascal’s Triangle by taking the numbers 1,2,6,20 as line of symmetry.

Solution:
Corresponding numbers are equal about the line of symmetry.

Objective Type Questions

Question 1.
The elements along the sixth row of the Pascal’s Triangle is
(i) 1,5,10,5,1
(ii) 1,5,5,1
(iii) 1,5,5,10,5,5,1
(iv) 1,5,10,10,5,1
Answer:
(iv) 1,5,10,10,5,1

Question 2.
The difference between the consecutive terms of the fifth slanting row containing four elements of a Pascal’s Triangle is
(i) 3,6,10,…
(ii) 4,10,20,…
(iii) 1,4,10,…
(iv) 1,3,6,…
Answer:
(ii) 4,10,20,…

Question 3.
What is the sum of the elements of ninth row in the Pascal’s Triangle?
(i) 128
(ii) 254
(iii) 256
(iv) 126
Answer:
(iii) 256

Students can Download Maths Chapter 5 Information Processing Ex 5.1 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 5 Information Processing Ex 5.1

Question 1.
Match the given patterns of shapes with the appropriate number pattern and its generalization.


Solution:
(i) (d)
(ii) (a)
(iii) (c)
(iv) (c)
(v) (b)

Objective Type Questions

Question 2.
Identify the correct relationship between x andy from the given table.

(i) y = 4x
(ii) y = x + 4
(iii) y = 4
(iv) y = 4 × 4
Answer:
(i) y = 4x

Question 3.
Identify the correct relationship between x and y from the given table.

(i) y = -2x
(ii) y = +2x
(iii) y = +3x
(iv) y = -3x
Answer:
(iv) y = -3x