Students can Download Maths Chapter 4 Statistics Ex 4.3 Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

Miscellaneous and Practice Problems

Question 1.
Draw a pie chart for the given table.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 1
Solution:
Converting the area in percentage into components parts of 360°, we have.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 2

Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 3

Question 2.
The data on modes of transport used by the students to come to school are given below. Draw a pie chart for the data.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 4
Solution:
Converting the percentage into components parts of 360°, we have
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 5
Mode of Transport by students.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 6

Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

Question 3.
Draw a histogram for the given frequency distribution.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 7
Solution:
The given distribution is discontinuous.
Lower boundary = lower limit — \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 41 – \(\frac { 1 }{ 2 } \) (1) = 40.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 45 + \(\frac { 1 }{ 2 } \) (1) = 45.5
Now continuous frequency table is as below
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 8

Question 4.
Draw a histogram and the frequency polygon in the same diagram to represent the following data.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 9
Solution:
The given distribution is discontinuous.
Lower boundary = lower limit – \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 50 – \(\frac { 1 }{ 2 } \) (1) = 49.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 55 + \(\frac { 1 }{ 2 } \) (1) = 55.5
∴ The continuous frequency table is as below.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 10

Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

Question 5.
The daily income of men and women is given below, draw a separate histogram for men and women.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 11
Solution:
The given data is continuous frequency distribution. So we take Income in X axis and No. of men in Y axis.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 12
Now we consider the number of women and their income we have.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 14

Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

Challenging Problems

Question 1.
Form a continuous frequency distribution table and draw histogram from the following data.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 16
Solution:
Converting into continuous distribution we have
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 17
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 18

Question 2.
A rupee spent in a cloth manufacturing company is distributed as follows. Represent this in a pie chart.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 19
Solution:
1 Rupee = 100 paise.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 20

Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3
Expenditure of a cloth manufacturing company.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 21

Question 3.
Draw a histogram for the following data.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 22
Solution:
Since mid values are given, the given distributors is discontinuous.
Lower boundary = lower limit — \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 15 – \(\frac { 1 }{ 2 } \) (10) = 10
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
15 + \(\frac { 1 }{ 2 } \) (10) = 20
The continuous distribution will be as follows.
Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3 23

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