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## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 3 Chapter 1 Fractions Ex 1.1

**6th Maths Guide Term 3 Question 1.**

Fill in the blanks.

(i) 7\(\frac{3}{4}\) + 6\(\frac{1}{2}\) = _______

(ii) The sum of whole number and a proper fraction is called ______

(iii) 5\(\frac{1}{3}\) – 3\(\frac{1}{2}\) = ______

(iv) 8 ÷ \(\frac{1}{2}\) = ______

(v) The number which has its own reciprocal is _______.

Solution:

(i) 14\(\frac{1}{4}\)

(ii) Mixed Fraction

(iii) 1\(\frac{5}{6}\)

(iv) 16

(v) 1

**Samacheer Kalvi 6th Maths Book Solutions Question 2.**

Say True or False

(i) 3\(\frac{1}{2}\) can be written as 3 + \(\frac{1}{2}\).

(ii) The sum of any two proper fractions is always an improper fraction.

(iii) The mixed fraction of \(\frac{13}{4}\) is 3\(\frac{1}{4}\).

(iv) The reciprocal of an improper fraction is always a proper fraction.

(v) 3\(\frac{1}{4}\) × 3\(\frac{1}{4}\) = 9\(\frac{1}{16}\)

Solution:

(i) True

(ii) False

(iii) True

(iv) True

(v) False

**6th Maths Guide 3rd Term Question 3.**

Answer the following :

Solution:

(i) Find the sum of \(\frac{1}{7}\) and \(\frac{3}{9}\)

(ii) What is the total of 3\(\frac{1}{3}\) and 4\(\frac{1}{6}\).

(iii) Simplify : 1\(\frac{3}{5}\) + 5\(\frac{4}{7}\)

(iv) Find the difference between \(\frac{8}{9}\) and \(\frac{2}{7}\)

(v) Subtract 1\(\frac{3}{5}\) and 2\(\frac{1}{3}\)

(vi) Simplify: 7\(\frac{2}{7}\) – 3\(\frac{4}{21}\)

**Samacheer Kalvi 6th Maths Book Solutions Term 3 Question 4.**

Convert mixed fraction into improper fractions and vice versa:

Solution:

**6th 3rd Term Maths Guide Question 5.**

Multiply the following :

Solution:

**Samacheer Kalvi 6th Maths Guide Term 3 Question 6.**

Divide the following:

Solution:

**6th Maths Term 3 Guide Question 7.**

Gowri purchased 3\(\frac{1}{2}\) kg of tomatoes, \(\frac{3}{4}\) kg of brinjal and 1\(\frac{1}{4}\) kg of onion, what is the total weight of the vegetables she bought?

Solution:

Weight of tomatoes Gowri purchased = 3\(\frac{1}{2}\) kg

Weight of Brinjal purchased = \(\frac{3}{4}\) kg

Total weight of vegetables that Gowri purchased = 5\(\frac{1}{2}\) kg

**6th Term 3 Maths Guide Question 8.**

An oil tin contains 3\(\frac{3}{4}\) litres of oil of which 2\(\frac{1}{2}\) litres of oil is used. How much oil is left over?

Solution:

Quantity of oil leftover = 1\(\frac{1}{4}\) litres.

**6th Maths Guide Term 3 Pdf Question 9.**

Nilavan can walk 4\(\frac{1}{2}\)km in an hour. How much distance will he cover in 3\(\frac{1}{2}\) hours?

Solution:

Distance walked by Nilavan in one hour = 4\(\frac{1}{2}\) km.

Nilavan walks 15\(\frac{3}{4}\) km in 3\(\frac{1}{2}\) hours

**6th Maths Term 3 Question 10.**

Ravi bought a curtain of length 15\(\frac{3}{4}\) m. If he cut the curtain into small pieces each of length 2\(\frac{1}{4}\) m, then how many small curtains will he get?

Solution:

**6th Third Term Maths Guide Objective Type Questions**

**Samacheer Kalvi 6th Maths Book Term 3 Question 11.**

Whcih of the following statement is incorrect?

Solution:

(d)\(\frac{10}{11}<\frac{9}{10}\)

Hint:

**Samacheer Kalvi 6th Maths Question 12.**

The difference between \(\frac{3}{7}\) and \(\frac{2}{7}\) is

Solution:

(a) \(\frac{13}{63}\)

Hint:

**6th Maths Term 3 Exercise 1.1 Question 13.**

The reciprocal of \(\frac{53}{17}\) is

Solution:

(c) \(\frac{17}{53}\)

Hint:

\(\frac{\frac{1}{53}}{\frac{53}{17}}=\frac{17}{53}\)

**6th Standard Maths Guide Term 3 Question 14.**

If \(\frac{6}{7}\) = \(\frac{A}{49}\), then the value of A is

(a) 42

(b) 36

(c) 25

(d) 48

Solution:

(a) 42

**Samacheer Kalvi Guru 6th Maths Question 15.**

Pugazh has been given four choices for his pocket money by his father. Which of the choices should he take in order to get the maximum money?

Solution:

(c) \(\frac{4}{5}\) of ₹150