Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.9

You can Download Samacheer Kalvi 11th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.9

Resolve the following rational expressions into partial fractions

11th Maths Exercise 2.9 Answers Question 1.

Solution:

11th Maths Exercise 2.9 Question 2.

Solution:

Exercise 2.9 Class 11 Question 3.

Solution:

11th Std Maths Exercise 2.9 Solutions Question 4.

Solution:

11th Maths Exercise 2.9 Solutions Question 5.

Solution:

Equating nuemarator on bothsides we get

Ex 2.9 Class 11 Maths Question 6.

Solution:

Equating numerator on both sides
(x – 2)² = A(x² + 1) + (Bx + c)(x)
Put x = 0
1 = A
Equating co-eff of x²
1 = A + B
(i.e.,) 1 + B = 1 ⇒ B = 0
put x = 1
A(2) + B + C = 0 (i.e.,) 2A + B + C = 0
2 + 0 + C = 0 ⇒ C = -2

11 Maths Exercise 2.9 Question 7.

Solution:
Since numerator and denominator are of same degree
we have divide the numerator by the denominator

Substituting the value in ….(1)

Question 8.

Solution:
Numerator is of greater degree than the denominator
So dividing Numerator by the denominator

⇒ 21x + 31 = A(x + 3) + B(x + 2)
Put x = -3
-63 + 31 = B(-1)
B = 32
Put x = -2
-42 + 31 = A(1) + B(0)
A = -11

11th Maths Exercise 2.9 3rd Sum Question 9.

Solution:

11th Maths Exercise 2.9 5th Sum Question 10.

Solution:

Equating Numerator on both sides we get
6x² – x + 1 = A(x² + 1) + (Bx + c)(x + 1)
6 + 1 + 1 = A(2) + 0 ⇒ 2A = 8 ⇒ A = 4
Equating co-eff of x²
6 = A + B
(i.e.,) 4 + B = 6 ⇒ B = 6 – 4 = 2
put x = 0
1 = A+ C
4 + C = 1 ⇒ C = 1 – 4 = -3

Samacheer Kalvi 11th Maths Example Sums Question 11.

Solution:
Since Numerator and are of same degree divide Numerator by the denominator

equating Numerator on both sides we get
x – 5 = A(x + 3) + B(x – 1)
Put x = -3
-3 -5 = A(0) + B(-4)
-4B = -8 ⇒ B = 2
Put x = 1
1 – 5 = A(4) + B(0)
4A = -4 ⇒ A = -1

Samacheer Kalvi Guru 11th Maths Question 12.

Solution:

Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.9 Additional Questions

Samacheer Kalvi 11 Maths Solutions Question 1.

Solution:

Samacheer Kalvi 11th Maths Question 2.

Solution:

Samacheer Kalvi 11th Maths Solution Question 3.

Solution:

Equating nemerator on b/s
9 = A(x+2)² + B(x – 1)(x + 2) + C(x – 1)
Put x = -2
9 = A(0) + B(0) + C(-3)
-3C = 9 ⇒ C = -3
Put x = 1
9 = A (1 + 2)² + B (0) + C(0)
9A = 9
A = 1
Put x = 0
9 = 4A – 2B – C
9 = 4(1) – 2B + 3
9 – 7 = -2B
2 = -2B
B = -1

Samacheer Kalvi 11th Maths Book Solutions Question 4.

Solution:

11 Maths Solutions Samacheer Question 5.

Solution:

0 = 0 + B(1 + 2)
3B = 0 ⇒ B = 0
Put x = -2
(-2)³ – 1 = A(-2 – 1) + B(0)
-8 – 1 = -3A
-9 = -3A
A = 9/3 ⇒ A = 3