You can Download Samacheer Kalvi 11th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.
Tamilnadu Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.13
Choose the correct or the most suitable questions.
Question 1.
If |x + 2| ≤ 9, then x belongs to
(a) (-∞, -7)
(b) [-11, 7]
(c) (-∞, -7) ∪ [11, ∞)
(d)(-11, 7)
Solution:
(b) [-11, 7]
Hint:
-x – 2 ≤ 9 x + 2 ≤ 9
-x < 9 + 2 = 11 x ≤ 9 – 2 = 7
⇒ x ≥ -11
so x ∈ [-11, 7]
Question 2.
Given that x, y and b are real numbers x < y, b ≥ 0, then ……..
(a) xb < yb (b) xb > yb
(c) xb ≤ vb
(d) xlb ≥ ylb
Solution:
(a) xb < yb
Hint:
Question 3.
(a) [2, ∞]
(b) (2, ∞)
(c) (-∞, 2)
(d) (-2, ∞)
Solution:
(b) (2, ∞)
Hint:
Question 4.
The solution of 5x – 1 < 24 and 5x + 1 > -24 is …….
(a) (4, 5)
(b) (-5, -4)
(c) (-5, 5)
(d) (-5, 4)
Solution:
(c) (-5, 5)
Hint:
Question 5.
The solution set of the following inequality |x – 1| ≥ |x – 3| is …….
(a) [0, 2]
(b) (2, ∞)
(c) (0, 2)
(d) (-∞, 2)
Solution:
(b) (2, ∞)
Question 6.
(a) 16
(b) 18
(c) 9
(d) 12
Solution:
(b) 18
Hint:
Question 7.
(a) -2
(b) -8
(c) -4
(d) -9
Solution:
(c) -4
Hint:
Question 8.
(a) 0.5
(b) 2.5
(c) 1.5
(d) 1.25
Solution:
(a) 0.5
Hint:
Question 9.
(a) 2
(b) 1
(c) 3
(d) 4
Solution:
(b) 1
Hint:
Question 10.
If 3 is the logarithm of 343, then the base is ……
(a) 5
(b) 7
(c) 6
(d) 9
Solution:
(b) 7
Hint.
⇒ logx343 = 3 ⇒ 343 = x3
(.i.e.,) 73 = x3 ⇒ x = 7
⇒ x = 7
Question 11.
Find a so that the sum and product of the roots of the equation 2x2 + (a – 3)x + 3a – 5 = 0 are equal is ……..
(a) 1
(b) 2
(c) 0
(d) 4
Solution:
(b) 2
Hint:
Question 12.
If a and b are the roots of the equation x2 – kx + 16 = 0 and satisfy a2 + b2 = 32, then the value of k is ……
(a) 10
(b) -8
(c) (-8, 8)
(d) 6
Solution:
(c) -8, 8
Hint:
a + b = k ….(1) ab = 16 ….(2)
a2 + b2 = (a + b)2 – 2ab = 32 .
k2 – 32 = 32 ⇒ k2 = 64 ⇒ k = ±8
Question 13.
The number of solutions of x2 + |x – 1| = 1 is ………
(a) 1
(b) 0
(c) 2
(d) 3
Solution:
(c) 2
We have two solutions 0, 1
Question 14.
The equations whose roots are numerically equal but opposite in sign to the roots of 3x2 – 5x – 7 = 0 is ……
(a) 3x2 – 5x – 7 = 0
(b) 3x2 + 5x – 7 = 0
(c) 3x2 – 5x + 7 = 0
(d) 3x2 + x – 7 = 0
Solution:
(b) 3x2 + 5x – 7 = 0
Hint:
Question 15.
If 8 and 2 are the roots of x2 + ax + c = 0 and 3, 3 are the roots of x2 + ax + b = 0, then the roots of the equation x2 + ax + b = 0 are …….
(a) 1, 2
(b) -1, 1
(c) 9, 1
(d) -1, 2
Solution:
(c) 9, 1
Hint:
Sum = 8 + 2 = 10 = -a ⇒ a = -10
Product = 3 × 3 = 9 = b ⇒ b = 9
Now the equation x2 + ax + b = 0
⇒ x2 – 10x + 9 = 0
⇒ (x- 9) (x – 1) = 0
x = 1 or 9
Question 16.
If a and b are the real roots of the equation x2 – kx + c = 0, then the distance
between the points (a, 0) and (b, 0) is ……..
Solution:
Hint:
a + b = k, ab = c
Question 17.
(a) 1
(b) 2
(c) 3
(d) 4
Solution:
(c) 3
Question 18.
(a) -1/2
(b) -2/3
(c) 1/2
(d) 2/3
Solution:
(a) -1/2
Hint:
Question 19.
The number of real roots of (x + 3)4 + (x + 5)4 = 16 is ……
(a) 4
(b) 2
(c) 3
(d) 0
Solution:
(a) 4
Hint:
The equation is (x + 3)4 + (x + 5)4 = 16
(x + 3)4 + (x + 5)4 = 24
This is biquadratic equation. It has 4 roots.
Question 20.
The value of log3 11 . log11 13 . log13 15 . log15 27 . log27 81 is …….
(a) 1
(b) 2
(c) 3
(d) 4
Solution:
(d) 4
Solution:
(d) 4
Hint.