You can Download Samacheer Kalvi 10th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.17

10th Maths Exercise 3.17 Answers Question 1.
If A = \(\left[\begin{array}{cc}{1} & {9} \\ {3} & {4} \\ {8} & {-3}\end{array}\right]=\left[\begin{array}{ll}{5} & {7} \\ {3} & {3} \\ {1} & {0}\end{array}\right]\) then verify that
(i) A + B = B + A
(ii) A + (-A) = (-A) + A = 0
Solution:
10th Maths Exercise 3.17 Answers Samacheer Kalvi Chapter 3 Algebra
Exercise 3.17 Class 10 Maths Solutions Chapter 3 Algebra Samacheer Kalvi

Exercise 3.17 Class 10 Question 2.
Ex 3.17 Class 10 Maths Solutions Chapter 3 Algebra Samacheer Kalvi
Solution:
10th Maths Exercise 3.17 Chapter 3 Algebra Samacheer Kalvi
10th New Syllabus Maths Exercise 3.17 Samacheer Kalvi Chapter 3 Algebra

Ex 3.17 Class 10 Question 3.
Find X and Y if X + Y = \(\left[\begin{array}{ll}{7} & {0} \\ {3} & {5}\end{array}\right]\) and X – Y = \(\left[\begin{array}{ll}{3} & {0} \\ {0} & {4}\end{array}\right]\)
Solution:
10th Maths Exercise 3.17 Samacheer Kalvi Chapter 3 Algebra
10th Samacheer Maths Solutions Chapter 3 Algebra Ex 3.17

10th Maths Exercise 3.17 Question 4.
If A = \(\left[\begin{array}{lll}{0} & {4} & {9} \\ {8} & {3} & {7}\end{array}\right]\), B = \(\left[\begin{array}{lll}{7} & {3} & {8} \\ {1} & {4} & {9}\end{array}\right]\) find the value of
(i) B – 5A
(ii) 3A – 9B
Solution:
Samacheer Kalvi 10th Guide Maths Solutions Chapter 3 Algebra Ex 3.17

10th New Syllabus Maths Exercise 3.17 Question 5.
Find the values of x, y, z if
Samacheer Kalvi Maths Book For 10th Standard Chapter 3 Algebra Ex 3.17
Solution:
(i) \(\left(\begin{array}{cc}{x-3} & {3 x-z} \\ {x+y+7} & {x+y+z}\end{array}\right)=\left(\begin{array}{ll}{1} & {0} \\ {1} & {6}\end{array}\right)\)
x – 3 = 1 ⇒ x = 4
3x – z = 0
3(4) – z = 0
-z = -12 ⇒ z = 12
x + y + 7 = 1
x + y = -6
4 + y = -6
y = -10
x = 4, y = -10, z = 12

(ii) \(\left[\begin{array}{ccc}{x} & {y-z} & {z+3}\end{array}\right]+\left[\begin{array}{lll}{y} & {4} & {3}\end{array}\right]=\left[\begin{array}{lll}{4} & {8} & {16}\end{array}\right]\)
x + y = 4 ……………. (1)
y – z + 4 = 8 ………….. (2)
z + 3 + 3 = 16 ………….. (3)
From (3), we get z = 10
From (2), we get y – 10 + 4 = 8
From (2), we get y = 14
From (1) we get x + 14 = 4
x = -10
x = -10, y = 14, z = 10

10th Maths Exercise 3.17 Samacheer Kalvi Question 6.
10th Maths Book Samacheer Kalvi Solutions Chapter 3 Algebra Ex 3.17
Solution:
10th Samacheer Kalvi Maths Book Back Answers Chapter 3 Algebra Ex 3.17

10th Samacheer Maths Question 7.
Find the non-zero values of x satisfying the matrix equation
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.17 10
Solution:
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.17 11

Samacheer Kalvi 10th Guide Maths Question 8.
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.17 12
Solution:
x2 – 4x = 5
y2 – 2y = 8
y2 – 2y – 8 = 0
(y – 4)(y + 2) = 0
y = 4, -2
x2 – 4x – 5 = 0
(x – 5)(x + 1) = 0
x = 5, -1
x = -1, 5, y = 4, -2

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