Students can Download Maths Chapter 1 Number System Ex 1.3 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 1.
Find the product of the following
(i) 0.5 × 3
(ii) 3.75 × 6
(iii) 50.2 × 4
(iv) 0.03 × 9
(v) 453.03 × 7
(vi) 4 × 0.7
Solution:
(i) 0.5 × 3
5 × 3 = 15
∴ 0.5 × 3 = 1.5

(ii) 3.75 × 6
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 1
375 × 6 = 2250
3.75 × 6 = 22.50

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

(iii) 50.2 × 4
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 2
502 × 4 = 2008
50.2 × 4 = 200.8

(iv) 0.03 × 9
3 × 9 = 27
0.03 × 9 = 0.27

(v) 453.03 × 7
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 3
45303 × 7 = 317121
453.03 × 7 = 3171.21

(vi) 4 × 0.7
4 × 7 = 28
4 × 0.7 = 2.8

Question 2.
Find the area of the parallelogram whose base is 6.8 cm and height is 3.5 cm.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 4
Base of the parallelogram b = 6.8 cm
Height of the parallelogram h = 3.5 cm
Area of the parallelogram A = b × h sq.units = 6.8 × 3.5 cm2
Area of the parallelogram = 23.80 cm2

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 3.
Find the area of the rectangle whose length is 23.7 cm and breadth is 15.2 cm.
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 5
Length of the rectangle l = 23.7 cm
Breadth of the rectangle b= 15.2 cm
Area of the rectangle A = l × b sq.units
= 23.7 × 15.2 cm2
Area of the rectangle = 360.24 cm2

Question 4.
Multiply the following

  1. 2.57 × 10
  2. 0.51 × 10
  3. 125.367 × 100
  4. 34.51 × 100
  5. 62.735 × 100
  6. 0.7 × 10
  7. 0.03 × 100
  8. 0.4 × 1000

Solution:

  1. 2.57 × 10 = 25.7
  2. 0.51 × 10 = 5.1
  3. 125.367 × 100 = 12536.7
  4. 34.51 × 100 = 3451
  5. 62.735 × 100 = 6273.5
  6. 0.7 × 10 = 7.0
  7. 0.03 × 100 = 3
  8. 0.4 × 1000 = 400

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 5.
A wheel of a baby cycle covers 49.7 cm in one rotation. Find the distance covered in 10 rotations.
Solution:
Length covered in 1 rotation = 49.7 cm
Length covered in 10 rotations = 49.7 × 10 cm = 497 cm

Question 6.
A picture chart costs ₹ 1.50. Radha wants to buy 20 charts to make an album. How much does she have to pay?
Solution:
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 6
Cost of 1 chart = ₹ 1.50
Cost of 20 charts = ₹ 1.50 × 20 = ₹ 30.00
Cost of 20 charts = ₹ 30

Question 7.
Find the product of the following.
(i) 3.6 × 0.3
(ii) 52.3 × 0.1
(iii) 537.4 × 0.2
(iv) 0.6 × 0.06
(v) 62.2 × 0.23
(vi) 1.02 × 0.05
(vii) 10.05 × 1.05
(viii) 101.01 × 0.01
(ix) 100.01 × 1.1
Solution:
(i) 3.6 × 0.3
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 7
36 × 3 = 108
3.6 × 0.3 = 1.08

(ii) 52.3 × 0.1
523 × 1 = 523
52.3 × 0.1 = 5.23

(iii) 537.4 × 0.2
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 8
5374 × 2 = 10748
537.4 × 0.2 = 107.48

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

(iv) 0.6 × 0.06
6 × 6 = 36
0.6 × 0.06 = 0.036

(v) 62.2 × 0.23
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 9
622 × 23 = 14306
62.2 × 0.23 = 14.306

(vi) 1.02 × 0.05
102 × 5 = 510
1.02 × 0.05 = 0.0510

(vii) 10.05 × 1.05
Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System 1.3 10
1005 × 105 = 105525
10.05 × 1.05 = 10.5525

(viii) 101.01 × 0.01
10101 × 1 = 10101
101.01 × 0.01 = 1.0101

(ix) 100.01 × 1.1
1001 × 11 = 110011
100.01 × 1.1 = 110.011

Objective Type Questions

Question 1.
1.07 × 0.1 _______
(i) 1.070
(ii) 0.107
(iii) 10.70
(iv) 11.07
Answer:
(ii) 0.107
Hint:
107 × 1 = 107
1.07 × 0.1 = 0.107

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 2.
2.08 × 10 = ______
(i) 20.8
(ii) 208.0
(iii) 0.208
(iv) 280.0
Answer:
(i) 20.8
Hint:
208 × 10 = 2080
2.08 × 10 = 20.80 = 20.8

Samacheer Kalvi 7th Maths Solutions Term 3 Chapter 1 Number System Ex 1.3

Question 3.
A frog jumps 5.3 cm in one jump. The distance travelled by the frog in 10 jumps is _______
(i) 0.53 cm
(ii) 530 cm
(iii) 53.0 cm
(iv) 53.5 cm
Answer:
(iii) 53.0 cm
Hint:
53 × 10 = 530
5.3 × 10 = 53.0

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