You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Question 1.

A School purchases some furniture and gets the following bill.

(i) What is the name of the store?

(ii) What is the serial number of the bill?

(iii) What is the cost of a blackboard?

(iv) How many sets of benches and desks does the school buy?

(v) Verify whether the total bill amount is correct.

Solution:

(i) Mullai Furniture Mart, Thanjavur

(ii) Serial No. 728

(iii) Cost of a blackboard is ₹ 3000

(iv) 50 sets

(v) Yes, the total bill amount is correct.

Question 2.

Prepare a bill for the following books of biographies purchased from Maruthu Book Store, Chidambaram on 12.04.2018 bearing the bill number 507.

10 copies of Subramanya Bharathiar @ ₹ 55 each, 15 copies of Thiruvalluvar @ ₹ 75 every 12 copies of Veeramamunivar @ ₹ 60 each and 12 copies of Thiru. Vi.Ka @ ₹ 70 each.

Solution:

Question 3.

Fillup the appropriate boxes in the following table.

Solution:

(i) Here Cost price < Selling price

Profit = S.P – C.P = 120 – 100 = ₹ 20

Here S.P > C.P

Profit = S.P – C.P = 120 – 110 = ₹ 10

(iii) Profit = ₹ 20

Profit = S.P. – C.P

⇒ 20 = S.P. – 120

⇒ 20 + 120 = S.P

⇒ S.P = ₹ 140

(iv) C.P = ₹ 100

S.P = ₹ 90

Here S.P < C.P

Loss = 100 – 90 = ₹ 10

(v) Profit = S.P – C.P

⇒ 25 = S.P – 120

⇒ 25 + 120 = S.P

⇒ S.P = ₹ 145

Question 4.

Fill up the appropriate boxes in the following table.

Solution:

(i) S.P. = M.P – Discount

S.P = ₹ 130

Here S.P > C.P

Profit = S.P – C.P = 130 – 110 = ₹ 20

(ii) S.P = M.P – Discount = 130 – 10 = ₹ 120

Here S.P > C.P

Profit = S.P – C.P = ₹ 120 – ₹ 110 = ₹ 10

(iii) S.P = M.P – Discount = 130 – 30 = ₹ 100

Here S.P < C.P

Loss = 110 – 100 = ₹ 10

(iv) C.P = ₹ 110

M.P = ₹ 120

Loss = ₹ 10

Loss = C.P – S.P

⇒ 10 = 110 – SP

⇒ SP = 110 – 10 = ₹ 100

Discount = M.P – S.P = 120 – 100 = ₹ 20

(v) M.P = ₹ 120

Discount = ₹ 10

Discount = M.P – S.P

⇒ 10 = 120 – S.P

⇒ S.P = 120 – 10 = ₹ 110

Profit = ₹ 20

Profit = S.P – C.P

⇒ 20 = 110 – C.P

⇒ C.P = 110 – 20 = 90

Question 5.

Rani bought a set of bangles for Rs 310. Her neighbour liked it most. So, Rani sold it to her for Rs 325. Find the profit or loss to Rani.

Solution:

CP = Rs 310

SP = Rs 325

Profit = SP – CP = Rs 325 – Rs 310 = Rs 15

Question 6.

Sugan bought a Jeans pant for ₹ 750. It did not fit him. He sold it to his friend for ₹ 710. Find the profit or loss to sugan.

Solution:

C.P of the Jeans pant = ₹ 750

S.P of the Jeans pant = ₹ 710

Here S.P < C.P

Loss = C.P – S.P = 750 – 710 = ₹ 40

Loss = ₹ 40

Question 7.

Somu bought a second hand bike for Rs 28,000 and spent Rs 2,000 on its repair. He sold it for Rs 30,000. Find his profit or loss.

Solution:

CP = Rs 28,000 + Rs 2,000

CP = Rs 30,000

SP = Rs 30,000

CP = SP

No profit / Loss

Question 8.

Muthu has a car worth ₹ 8,50,000 and he wants to sell it at a profit of ₹ 25,000. What should be the selling price of the car? Solution:

Cost price of the car = ₹ 8,50,000

Expected profit = ₹ 25,000

We know that profit = S.P – C.P

25000 = S.P – 8,50,000

⇒ 25,000 + 8,50,000 = S.P

⇒ S.P = 8,75,000

Selling Price of the car should be ₹ 8,75,000

Question 9.

Valarmathi sold her pearl set for Rs 30,000 at profit of Rs 5,000. Find the cost price of the pearl set.

Solution:

SP = Rs 30,000

Profit = Rs 5,000

CP = SP – Profit

= Rs 30,000 – Rs 5,000

= Rs 25,000

Question 10.

If Guna marks his product to be sold for ₹ 325 and gives a discount of ₹ 30, then find the S.P.

Solution:

Marked Price of the Product = ₹ 325

Discount = ₹ 30

Selling Price = M.P – Discount = 325 – 30 = ₹ 295

S.P. = ₹ 295

Question 11.

A man buys a chair for 1,500. He wants to sell it at a profit of Rs 250 after making a discount of Rs 100. What is the M.P. of the chair?

Solution:

CP = Rs 1,500

Profit = Rs 250

SP = CP + Profit

= Rs 1,500 + Rs 250

= Rs 1,750

Discount = Rs 100

SP = MP – Discount

MP = SP + Discount

= Rs 1,750 + Rs 100

= Rs 1,850

Question 12.

Amutha marked her home product of pickle as ₹ 300 per pack. But she sold it for only ₹ 275 per pack. What was the discount offered by her per pack?

Solution:

M.P of the pickle = ₹ 300

S.P = ₹ 275

S.P = M.P – Discount

⇒ 275 = 300 – Discount

⇒ Discount = 300 – 275 = ₹ 25

Discount per pack = ₹ 25

Question 13.

Valavan bought 24 eggs for Rs 96. Four of them were broken and also he had a loss of Rs 36 on selling them. What is the selling price of one egg?

Solution:

Cost of 24 eggs = Rs 96

Since 4 of the eggs were broken, the number of remaining eggs = 24 – 4 = 20

Since the loss is Rs 36

Selling price of 20 eggs

SP = CP – Loss

= Rs 96 – Rs 36

= Rs 60

∴ Cost of 1 egg = Rs 60 / 20 = Rs 3

Question 14.

Mangai bought a cell phone for ₹ 12,585. It fell down. She spent ₹ 500 on it repair. She sold it for ₹ 7,500. Find her profit or loss.

Solution:

Cost of the cell phone = ₹ 12,585

Spent on repairs = ₹ 500

Cost price = Cost of cell phone + repair charge = 12,585 + 500 = ₹ 13,085

S.P. = 7,500

Here C.P > S.P

∴ It is loss

Loss = C.P – S.P = 13,085 – 7500 = ₹ 5,585

Loss = ₹ 5,585

**Objective Type Questions**

Question 15.

Discount is subtracted from ……… to get S.P.

(a) M.P

(b) C.P

(c) Loss

(d) Profit

Solution:

(a) M.P

Question 16.

‘Overhead expenses’ is always included in _____.

(a) S.P

(b) C.P.

(c) Profit

(d) Loss

Solution:

(b) C.P.

Question 17.

There is no profit or loss when

(a) C.P = S.P

(b) C.P > S.P

(c) C.P < S.P

(d) M.P = Discount

Solution:

(a) C.P = S.P

Question 18.

Discount = M.P _____

(a) Profit

(b) S.P

(c) Loss

(d) C.P

Solution:

(b) S.P