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## Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 4 Geometry Ex 4.6

**9th Maths Geometry Exercise 4.6 Question 1.**

Draw a triangle ABC, where AB = 8 cm, BC = 6 cm and ∠B = 70° and locate its circumcentre and draw the circumcircle.

Solution:

∆ABC, where AB = 8 cm,

BC = 6 cm,

B = 70°

Construction:

(i) Draw the ∆ABC with the given measurements.

(ii) Construct the perpendicular bisector at any two sides (AB and BC) and let them meet at S which is the circumcircle.

(iii) S as centre and SA = SB = SC as radius, draw the circumcircle to pass through A, B, and C. Circum radius = 4.3 cm.

**9th Maths Exercise 4.6 Question 2.**

Construct the right triangle PQR whose perpendicular sides are 4.5 cm and 6 cm. Also locate its circumcentre and draw the circumcircle.

Solution:

Right triangle PQR whose perpendicular sides are 4.5 cm and 6 cm

Construction :

(i) Draw the right triangle PQR with the given measurements.

(ii) Construct the perpendicular bisector at any two sides (PQ and QR) and let them meet at S which is the circumcentre.

(iii) S as centre and SP = SQ = SR as radius, draw the circumcircle to pass through P, Q and R. Circumradius = 3.7 cm.

**9th Maths Geometry Exercise 4.6 In Tamil Question 3.**

Construct ∆ABC with AB = 5 cm ∠B = 100° and BC = 6 cm. Also locate its circumcentre draw circumcircle.

Solution:

Construction :

(i) Draw the ∆ABC with the given measurements.

(ii) Construct the perpendicular bisector at any two sides (BC and AC) and let them meet at S which is the circumcentre.

(iii) S as centre and SA = SB = SC as radius, draw the circumcircle to pass through A, B, and C. Circumradius = 4.3 cm.

**Ex 4.6 Class 9 Maths Question 4.**

Construct an isosceles triangle PQR where PQ = PR and ∠Q = 50°, QR = 7cm. Also draw its circumcircle.

Solution:

Isosceles triangle PQR where PQ = PR and Q = 50°, QR = 7 cm.

Construction :

(i) Draw the ∆PQR with the given measurements.

(ii) Construct the perpendicular bisector at any two sides (PQ and QR) and let them meet at S which is the circumcentre.

(iii) S as centre and SP = SQ = SR as radius, draw the circumcircle to pass through P, Q, R. Circumradius = 3.5 cm.

**9th Standard Maths Exercise 4.6 Question 5.**

Draw an equilateral triangle of sides 6.5 cm and locate its incentre. Also draw the incircle.

Solution:

Side = 6.5 cm

Construction :

Step 1 : Draw ∆ABC with AB = BC = CA = 6.5 cm

Step 2 : Construct angle bisectors of any two angles (A and B) and let them meet at I.I is the incentre of ∆ABC.

Step 3 : Draw perpendicular from I to any one of the side (AB) to meet AB at D.

Step 4 : With I as centre, ID as radius draw the circle. This circle touches all the sides of triangle internally.

Step 5 : Measure in radius. In radius = 1.9 cm.

**Exercise 4.6 Class 9 Maths Question 6.**

Draw a right triangle whose hypotenuse is 10 cm and one of the legs is 8 cm. Locate its incentre and also draw the incircle.

Solution:

hypotenuse = 10 cm

One of the legs = 8 cm

Step 1 : Draw AABC with BC = 8 cm. AC = 10 cm with right angle at B.

Step 2 : Construct angle bisectors of any two angles (B and C) and let them meet at 1.1 is the incentre.

Step 3 : Draw perpendicular from I to any side of the triangle to meet BC at D.

Step 4 : With I as centre, ID as radius draw the incircle, which touches all the three sides of the triangle internally. In radius = 1.9 cm.

**9th Maths Geometry Exercise 4.6 Solutions Question 7.**

Draw ∆ABC given AB = 9 cm, ∠CAB = 115° and ∆ABC = 40°. Locate its incentre and also draw the incircle. (Note: You can check from the above examples that the incentre of any triangle is always in its interior).

Solution:

Construction :

Step 1 : Draw ∆ABC with AB = 9 cm. ∠A = 115°,∠B = 40°.

Step 2 : Construct angle bisectors of any two angles (B and C). Let them meet at I.I is the incentre of ∆ABC.

Step 3 : Draw perpendicular from I to any side (BC) to meet BC at D.

Step 4 : Draw incircle, with I as centre and ID a radius. Measures the in radius.

**9th Geometry 4.6 Question 8.**

Construct ∆ABC in which AB = BC = 6 cm and B = 80° . Locate its incentre and draw the incircle.

Solution:

In ∆ABC, AB = BC = 6 cm, ∠B = 80°.

Construction :

Step 1 : Draw AABC with BC = 6 cm. AB = 6 cm, AB = 6 cm, and ∠B = 80°.

Step 2 : Construct the incentre I and ID is the in radius, as in the previous sums.

Step 3 : Draw incircle with I as centre and ID as radius. It touches all the three sides internally.

Step 4 : Measure in radius. In radius = 1.7