You can Download Samacheer Kalvi 11th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6

Question 1.
Find the zeros of the polynomial function f(x) = 4x2 – 25
Solution:
Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 1

Question 2.
If x = -2 is one root of x3 – x2 – 17x = 22, then find the other roots of equation.
Solution:
x = – 2 is one root
So applying synthetic division
Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 13

Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6

Question 3.
Find the real roots of x4 = 16
Solution:
x4 = 16
⇒ x4 – 16 = 0
(i.e.,) x4 – 42 = 0
⇒ (x2 + 4)(x2 – 4) = 0
x2 + 4 = 0 will have no real roots
so solving x2 – 4 = 0
x2 = 4
Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 14

Question 4.
Solve (2x + 1)2 – (3x + 2)2 = 0
Solution:
Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 15

Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 Additional Questions

Question 1.
Find the zeros of the polynomial function f(x) = 9x2 – 36
Solution:
Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 16

Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6

Question 2.
If x = 2 is one root of x3 + 2x2 – 5x – 6 = 0 then find the other roots of the equation
Solution:
x = 2 is a root
so applying synthetic division
Samacheer Kalvi 11th Maths Solutions Chapter 2 Basic Algebra Ex 2.6 17
∴ The other factor is x2 + 4x + 3
Now x3 + 2x2 – 5x – 6 = (x – 2)(x2 + 4x + 3)
∴ x3 + 2x2 – 5x – 6 = 0 ⇒ (x – 2)(x2 + 4x + 3)
x – 2 = 0 or x2 + 4x + 3 = 0
x = 2 or (x + 1)(x + 3) = 0
⇒ x = -1 or -3
so the roots are x = -1, 2, -3

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