{"id":589,"date":"2023-11-06T07:47:36","date_gmt":"2023-11-06T02:17:36","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=589"},"modified":"2023-11-07T16:30:16","modified_gmt":"2023-11-07T11:00:16","slug":"samacheer-kalvi-9th-maths-chapter-1-additional-questions","status":"publish","type":"post","link":"https:\/\/samacheerkalviguru.com\/samacheer-kalvi-9th-maths-chapter-1-additional-questions\/","title":{"rendered":"Samacheer Kalvi 9th Maths Solutions Chapter 1 Set Language Additional Questions"},"content":{"rendered":"

You can Download Samacheer Kalvi 9th Maths Book Solutions<\/a>\u00a0Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 1 Set Language Additional Questions<\/h2>\n

Text Book Activities<\/span><\/p>\n

Question 1.
\nDiscuss and give as many examples of collections from your daily life situations, which are sets and which are not sets.
\nSolution:
\nWhich are sets<\/p>\n

    \n
  1. Collection of pen<\/li>\n
  2. Collection of dolls<\/li>\n
  3. Collection of books<\/li>\n
  4. Collection of red flower etc.<\/li>\n<\/ol>\n

    Which are not sets<\/p>\n

      \n
    1. Collection of good students in a class.<\/li>\n
    2. Collection of beautiful flowers in a garden etc.<\/li>\n<\/ol>\n

      Question 2.
      \nWrite the following sets in respective forms.
      \nSolution:
      \n\"Samacheer<\/p>\n

      Question 3.
      \nFill in the blanks with appropriate cardinal numbers.
      \nSolution:
      \n\"Samacheer<\/p>\n

      \"Samacheer<\/p>\n

      Additional Questions and Answers<\/span><\/p>\n

      Exercise 1.1<\/span><\/p>\n

      Question 1.
      \nLet A = {0, 1, 2, 3, 4, 5}. Insert the appropriate symbol G or g in the blank spaces,
      \n(i) 0 ___ A
      \n(ii) 6 ___ A
      \n(iii) 3 ___ A
      \n(iv) 4 ____ A
      \n(v) 7 ____ A
      \nSolution:
      \n(i) 0 \u2208 A
      \n(ii) 6 \u2209 A
      \n(iii) 3 \u2208 A
      \n(iv) 4 \u2208 A
      \n(v) 7 \u2209 A<\/p>\n

      Question 2.
      \nWrite the following in Set-Builder form.
      \n(i) The set of all positive even numbers.
      \n(ii) The set of all whole numbers less than 20.
      \n(iii) The set of all positive integers which are multiple of 3.
      \n(iv) The set of all odd natural numbers less than 15.
      \n(v) The set of all letters in the word \u2018computer\u2019.
      \nSolution:
      \n(i) A = {x : x is a positive even number}
      \n(ii) B = {x : x is a whole number and x < 20}
      \n(iii) C = {x : x is a positive integer and multiple of 3}
      \n(iv) D = {x : x is an odd natural number and x < 15}
      \n(v) E = {x : x is a letter in the word \u201cComputer\u201d}<\/p>\n

      \"Samacheer<\/p>\n

      Question 3.
      \nWrite the following sets in Roster form.
      \n(i) A = {x : x \u2208 N, 2< x < 10 }
      \n(ii) B = {x : x \u2208 Z, –\\(\\frac { 1 }{ 2 }\\) < x < \\(\\frac { 11 }{ 2 }\\) }
      \n(iii) C = {x : x is a prime number and a divisor of 6 }
      \n(iv) x = {x : x = 2n<\/sup>, it n \u2208 N and n \u2264 5}
      \n(v) M = {x : x = 2y – 1, y \u2264 5, j \u2208 W}
      \nSolution:
      \n(i) A = {3,4, 5, 6, 7, 8, 9}
      \n(ii) B = {0, 1, 2, 3, 4, 5}
      \n(iii) C = {2, 3}
      \n(iv) Given, x = 2n<\/sup>, n \u2208 N and n \u2264 5.
      \nHere n = 1, 2, 3, 4, 5
      \nn = 1 \u21d2 21 = 2
      \nn = 2 \u21d2 22 = 4
      \nn = 3 \u21d2 23 = 8
      \nn = 4 \u21d2 24 = 16
      \nn = 5 \u21d2 25 = 32
      \nX = {2, 4, 8, 16, 32}<\/p>\n

      (v) Given, x = 2y – 1, y \u2264 5 and y \u2208 W Here j = 0, 1,2, 3, 4, 5
      \ny = 0 \u21d2 x = 2 (0) – 1 = -1
      \ny = 1 \u21d2 x = 2 (1) – 1 = 2 – 1 = 1
      \ny = 2 \u21d2 x = 2 (2) – 1 = 4 – 1 = 3
      \ny = 3 \u21d2 x = 2 (3) – 1 = 6 – 1 = 5
      \ny = 4 \u21d2 x = 2 (4) – 1 = 8 – 1 = 7
      \ny = 5 \u21d2 x = 2 (5) – 1 = 10 – 1= 9
      \nM = {-1, 1, 3, 5, 7, 9}<\/p>\n

      Exercise 1.2<\/span><\/p>\n

      Question 1.
      \nFind the number of subsets and number of proper subsets of a set X = {a, b, c, x, y, z}.
      \nSolution:
      \nGiven X = {a, b, c, x, y, z}.
      \nThen, n(X) = 6
      \nThe number of subsets = n[P(X)] = 26<\/sup> = 64
      \nThe number of proper subsets = n[P(X)] – 1 = 26<\/sup> – 1 = 64 – 1 = 63<\/p>\n

      Question 2.
      \nFind the cardinal number of the following sets.
      \n(i) A = {x : x is a prime factor of 12}.
      \n(ii) B = {x : x \u2208 W, x \u2264 5}.
      \n(iii) X = {x : x is an even prime number}
      \nSolution:
      \n(i) Factors of 12 are 1, 2, 3, 4, 6, 12. So, the prime factors of 12 are 2,3.
      \nWe write the set A in roster form as A = {2, 3} and hence n(A) = 2.
      \n(ii) In Tabular form B = {0, 1, 2, 3, 4, 5}
      \nThe set B has six elements and hence n(B) = 6
      \n(iii) X = {2} [2 is the only even prime number]
      \n\u2234 n (X) = 1<\/p>\n

      Question 3.
      \nState whether the following sets are finite or infinite.
      \n(i) A = {x : x is a multiple of 5, x \u2208 N}.
      \n(ii) B = {0,1, 2, 3, 4, 75}.
      \n(iii) The set of all positive integers greater than 50.
      \nSolution:
      \n(i) A = {5, 10, 15, 20, …… } \u2234A is an infinite set
      \n(ii) Finite
      \n(iii) Let X be the set of all positive integers greater than 50
      \nThen X= (51, 52, 53, ….. }
      \n\u2234 X is an infinite set.<\/p>\n

      Question 4.
      \nWhich of the following sets are equal?
      \n(i) A = (1, 2, 3, 4}, B = {4, 3, 2, 1}
      \n(ii) A = (4, 8, 12, 16}, B = (8, 4, 16, 18}
      \n(iii) X ={2, 4, 6, 8}
      \nY = {x : x is a positive even integer and 0 < x < 10}
      \nSolution:
      \n(i) Since A and B contain exactly the same elements, A and B are equal sets.
      \n(ii) A and B has different elements.
      \n\u2234 A and B are not equal sets.
      \n(iii) X = {2, 4, 6, 8}, Y = {2, 4, 6, 8}
      \n\u2234 X and Y are equal sets.<\/p>\n

      Question 5.
      \nWrite \u2286 or \u2288 in each blank to make a true statement.
      \n(i) {4, 5, 6, 7} ____ {4, 5, 6, 7, 8}
      \n(ii) {a, b, c} ____ {b, e, f, g}
      \nSolution:
      \n(i) {4, 5, 6, 7} \u2288 {4, 5, 6, 7, 8}
      \n(ii) {a, b, c} \u2288 {b, e, f, g}<\/p>\n

      \"Samacheer<\/p>\n

      Question 6.
      \nWrite down the power set of A= {3, {4, 5}}.
      \nSolution:
      \nThe subsets of A are {\u00d8, {3}, {4, 5}, {3,{4, 5}}
      \nP(A) = {\u00d8, {3}, {4,5}, {3{4,5}}<\/p>\n

      Exercise 1.3<\/span><\/p>\n

      Question 1.
      \nFind the union of the following sets.
      \n(i) A = {1, 2, 3, 5, 6} and B = {4, 5, 6, 7, 8}
      \n(ii) X = {3, 4, 5} and Y = \u00d8
      \nSolution:
      \n(i) A \u222a B = {1, 2, 3, 4, 5, 6, 7, 8}
      \n(ii) X \u222a Y = {3, 4, 5}<\/p>\n

      Question 2.
      \nFind A \u2229 B if (i) A = {10, 11, 12, 13}, B = {12, 13, 14, 15}, (ii) A = {5, 9, 11}, B = \u00d8.
      \nSolution:
      \n(i) A \u2229 B = {12, 13}
      \n(ii) A \u2229 B = \u00d8<\/p>\n

      Question 3.
      \nGiven the sets A = {4, 5, 6, 7} and B = {1, 3, 8, 9}, find A \u2229 B.
      \nSolution:
      \nA \u2229 B = \u00d8<\/p>\n

      Question 4.
      \nIf A= {-2, -1, 0, 3, 4}, B = {-1, 3, 5}, find (i) A – B, (ii) B – A.
      \nSolution:
      \n(i) A – B = {-2, 0, 4}
      \n(ii) B – A = {5}<\/p>\n

      Question 5.
      \nIf A = {2, 3, 5, 7,11} and B = {5, 7, 9, 11, 13}, find A \u2206 B.
      \nSolution:
      \nA \u2206 B= {2, 3, 9, 13}<\/p>\n

      Question 6.
      \nDraw a venn diagram similar to one at the side and shade the regions representing the following sets (i) A’, (ii) B’, (iii) A’ \u222a B’, (iv) (A \u222a B)’, (v) A’ \u2229 B’
      \nSolution:
      \n(i) A’
      \n\"Samacheer<\/p>\n

      (ii) B’
      \n\"Samacheer<\/p>\n

      (iii) A’ \u222a B’
      \n\"Samacheer<\/p>\n

      (iv) (A \u222a B)’
      \n\"Samacheer<\/p>\n

      (v) A’ \u2229 B’
      \n\"Samacheer<\/p>\n

      Question 7.
      \nState which of the following sets are disjoint.
      \n(i) A = {2, 4, 6, 8}, B = {x : x is an even number < 10, x \u2208 N}
      \n(ii) X = {1, 3, 5, 7, 9}, Y = {0, 2, 4, 6, 8, 10}
      \n(iii) R = {a, b, c, d, e}, S = {d, e, b, c, a}
      \nSolution:
      \n(i) A = {2, 4, 6, 8}, B = {2, 4, 6, 8}
      \nA \u2229 B = {2, 4, 6, 8} \u2260 \u00d8
      \n\u2234 A and B are not disjoint sets.
      \n(ii) X \u2229 Y = { } = \u03a6, X and Y are disjoint sets.
      \n(iii) R \u2229 S = {a, b, c, d, e} \u2260 \u00d8
      \n\u2234 R and S are not disjoint sets.<\/p>\n

      \"Samacheer<\/p>\n

      Question 8.
      \nIf A = {a, b, c, d, e}and B = {a, e, i, o, u} find AB.
      \nSolution:
      \nA \u2229 B = {a, b, c, d, e} \u2229 {a, e, i, o, u} = {a, e}<\/p>\n

      Exercise 1.4<\/span><\/p>\n

      Question 1.
      \nIf A and B are two sets containing 13 and 16 elements respectively, then find the minimum and maximum number of elements in A \u222aB?
      \nSolution:
      \n\"Samacheer
      \nn(A) = 13 ; n(B) = 16
      \nMinimum n(A \u222a B) = 16
      \nMaximum n(A \u222a B) = 13 + 16 = 29<\/p>\n

      Question 2.
      \nIf n(U) = 38, n(A) = 16, n(A \u2229 B) = 12, n(B’) = 20, find n(A \u222a B).
      \nSolution:
      \n\"Samacheer
      \nn(U) = 38
      \nn(A) = 16
      \nN(A \u2229 B) = 12
      \nn(B’) = 20
      \nn(A \u222a B) = ?
      \nHint: n(B) = n(U) – n(B)’
      \nn(B) = 38 – 20
      \nn(B) = 18
      \nn(A \u222a B) = n(A) + n(B) – n (A \u2229 B)
      \nn(A \u222a B) = 16 – 12 + 18
      \nn(A \u222a B) = 4 + 18 = 22.<\/p>\n

      Question 3.
      \nLet A = {b, d, e, g, h} and B = {a, e, c, h} verify that n(A – B) = n(A) – n(A \u2229 B)
      \nSolution:
      \nA = {b, d, e, g, h),
      \nB = {a, e, c, h}
      \nA \u2229 B = {b, d, g}
      \nn(A \u2229 B) = 3 ………….. (1)
      \nA \u2229 B = {e, h}
      \nn(A \u2229 B) = 2, n(A) = 5
      \nn(A) – n(A \u2229 B) = 5 – 2 = 3 ……………… (2)
      \nForm (1) and (2) we get
      \nn(A – B) = n(A) – n(A \u2229 B)<\/p>\n

      Question 4.
      \nIf A = {2, 5, 6, 7} and B = {3, 5, 7, 8}, then verify the commutative property of
      \n(i) union of sets
      \n(ii) intersection of sets
      \nSolution:
      \nGiven, A = {2, 5, 6, 7} and B = {3, 5, 7, 8}
      \n(i) A \u222a B = {2, 3, 5, 6, 7, 8} ……………. (1)
      \nB \u222a A = {2, 3, 5, 6, 7, 8} …………… (2)
      \nFrom (1) and (2) we have A \u222a B = B \u222a A
      \nIt is verified that union of sets is commutative.<\/p>\n

      (ii) A n B = {5, 7} …………… (3)
      \nB n A = {5, 7} ……………. (4)
      \nFrom (3) and (4) we get, A \u2229 B = B \u2229 A
      \nIt is verified that intersection of sets is commutative.<\/p>\n

      \"Samacheer<\/p>\n

      Question 5.
      \nIf A = {b, c, d, e} and B = {b, c, e, g} and C = {a, c, e}, then verify A \u222a (B \u222a C) = (A \u222a B) \u222a C.
      \nSolution:
      \nGiven, A = {b, c, d, e} and B = {b, c, e, g} and C = {a, c, e}
      \nNow B \u222a C = {a, b, c, e, g}
      \nAu(B \u222aC) = {a, b, c, d, e, g} ……………. (1)
      \nThen, A \u222a B = {b, c, d, e, g}
      \n(A \u222a B) \u222a C = {a, b, c, d, e, g} ……………… (2)
      \nFrom (1) and (2) it is verified that
      \nA \u222a (B \u222a C) = (A \u222a B) \u222a C<\/p>\n

      Exercise 1.5<\/span><\/p>\n

      Question 1.
      \nIf A = {1, 3, 5, 7, 9}, B = {x : x is a composite number and x < 12} and C = {x : x \u2208 N and 6 < x < 10} then verify A \u222a (B \u2229 C) = (A \u222a B) \u2229 (A \u222a C).
      \nSolution:
      \nGiven, A = {1, 3, 5, 7, 9} and B = {4, 6, 8, 9, 10}and C = {6, 7, 8, 9}
      \nB \u2229 C = {4, 6<\/span>, 8<\/span>, 9, 10} n {6<\/span>, 7, 8<\/span>, 9<\/span>} = {6, 8, 9}
      \nA \u222a (B \u2229 C) = {1, 3, 5, 6, 7, 8, 9} ……………. (1)
      \nThen (A \u222a B) = {1, 3, 5, 7, 9} \u222a {4, 6, 8, 9, 10} = {1, 3, 4, 5, 6, 7, 8, 9, 10}
      \n(A \u222a C) = {1, 3, 5, 7, 9} \u222a {6, 7, 8, 9} = {1,3, 5, 6, 7, 8, 9}
      \n(A \u222a B) \u2229 (A \u222a C) = {1<\/span>, 3<\/span>, 4, 5<\/span>, 6<\/span>, 7<\/span>, 8<\/span>, 9<\/span>, 10} \u2229 {1<\/span>, 3<\/span>, 5<\/span>, 6<\/span>, 7<\/span>, 8<\/span>, 9<\/span>}
      \n= {1, 3, 5, 6, 7, 8, 9} …………….. (2)
      \nFrom (1) and (2), it is verified that
      \nA \u222a (B \u2229C) = (A \u222a B) \u2229 (A \u222a C)<\/p>\n

      Question 2.
      \nIf A, B and C are overlapping sets, draw venn diagram for : A \u2229 B
      \nSolution:
      \n\"Samacheer<\/p>\n

      Question 3.
      \nDraw Venn diagram for A \u2229 B \u2229 C
      \nSolution:
      \n\"Samacheer<\/p>\n

      Question 4.
      \nIf P = {x : x \u2208 N and 1 < x < 11}, Q = {x : x = 2n, n \u2208 N and it < 6} and R = {4, 6, 8, 9, 10, 12}, then verify P – (Q \u2229 R) = (P – Q) \u222a (P – R).
      \nSolution:
      \nThe roster form of sets P, Q and R are P = {2, 3, 4, 5, 6, 7, 8, 9, 10}, Q = {2, 4, 6, 8, 10} and R = {4, 6, 8, 9, 10, 12}
      \nFirst, we find Q \u2229 R = {4, 6, 8, 10}
      \nThen, P – (Q \u2229 R) = {2, 3, 5, 7, 9} ………….. (1)
      \nNext, P – Q = {3, 5, 7, 9}
      \nand P – R = {2, 3, 5, 7}
      \nand so, (P – Q) \u222a (P – Q) = {2, 3, 5, 7, 9} ……………. (2)
      \nHence from (1) and (2), it verified that P – (Q \u2229 R) = (P – Q) \u222a (P – R)
      \nFinding the elements of set Q
      \nGiven, x = 2 n
      \nn = 1 \u2192 x = 2 (1) = 2
      \nn = 2 \u2192 x = 2(2) = 4
      \nn = 3 \u2192 x = 2 (3) = 6
      \nn = 4 \u2192 x = 2(4) = 8
      \nn = 5 \u2192 x = 2(5) = 10
      \nTherefore, x takes values such as 2, 4, 6, 8, 10<\/p>\n

      \"Samacheer<\/p>\n

      Question 5.
      \nIf U = {x : x \u2208 Z, -3 < x \u2264 9}, A = {x : x = 2P + 1, P \u2208 Z , -2 \u2264 P \u2264 3}, B = {x : x = q + l, q \u2208 Z, 0 \u2264 q \u2264 3}, verify De Morgan’s laws for complementation.
      \nSolution:
      \nGiven, U = {-3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
      \nA = {-3, -1, 1, 3, 5, 7} and B = {1, 2, 3, 4}
      \nLaw (i) (A \u222a B)’ = A’ \u2229 B’
      \nNow, A \u222a B = {-3, -1, 1, 2, 3, 4, 5, 7}
      \n(A \u222a B)’ = {-2, 0, 6, 8, 9} ………….. (1)
      \nThen, A’ = {-2, 0, 2, 4, 6, 8, 9) and
      \nB’ = {-3, -2, -1, 0, 5, 6, 7, 8, 9}
      \nA’ \u2229 B’ = {-2, 0, 6, 8, 9} ……………… (2)
      \nFrom (1) and (2) it is verified that
      \n(A \u222a B)’ = A’ \u2229 B’
      \nLaw (ii) (A \u2229 B)’ = A’ \u222a B’
      \nNow, A \u2229 B = {1, 3}
      \n(A \u2229 B)’ = {-3, -2, -1, 0, 2, 4, 5, 6, 7, 8, 9} ………….. (3)
      \nThen, A’ \u222a B’ = {-3, -2, -1, 0, 2, 4, 5, 6, 7, 8, 9} ………………. (4)
      \nFrom (3) and (4) it is verified that
      \n(A \u2229 B)’ = A’ \u222a B’<\/p>\n

      Exercise 1.6<\/span><\/p>\n

      Question 1.
      \nFrom the given venn diagram. Find (i) A, (ii) B, (iii) A \u222a B (iv) A \u2229 B also verify that n(A \u222aB) = n(A) + n(B) – n(A \u2229 B).
      \n\"Samacheer
      \nSolution:
      \nA = {a, b, d, e, g, h}
      \nB = {b, c, e, f, h, i, j}
      \nA \u222a B = {a, b, c, d, e, f, g, h, i, j}
      \nA \u2229 B = {b, e, h}
      \nSo, n(A) = 6, n(B) = 7, n(A \u222aB) = 10, n(A \u2229 B) = 3
      \nNow, n(A) + n(B) – n(A \u2229 B) = 6 + 7 – 3 = 10
      \nHence, n(A) + n(B) – n(A \u2229 B) = n(A \u222a B)<\/p>\n

      Question 2.
      \nIf n(A) = 12, n(B) = 17 and n(A \u222a B) = 21, find n(A \u2229B).
      \nSolution:
      \nGiven that n(A) = 12, n(B) = 17 and n(A \u222a B) =21
      \nBy using the formula n(A \u222a B) = n(A) + n(B) – n(A \u2229 B)
      \nn(A \u2229 B) = 12 + 17 – 21 = 8<\/p>\n

      Question 3.
      \nIn a school, 80 students like Maths, 90 students like Science, 82 students like History, 21 like both Maths and Science, 19 like both Science and History 20 like both Maths and History and 8 liked all the three subjects. If each student like atleast one subject, then find (i) the number of students in the school (ii) the number of students who like only one subject.
      \nSolution:
      \nLet M, S and H represent sets of students who like Maths, Science and History respectively.
      \nThen, n(M) = 80, n(S) = 90, n(H) = 82, n(M \u2229 S) = 21, n(S \u2229 H) = 19, n(M \u2229 H) = 20, n(M \u2229 S \u2229 H) = 8
      \nLet us represents the given data in a venn diagram.
      \n\"Samacheer
      \n(i) The number of student in the school = 52 + 59 + 55 + 12 + 11 + 8 + 8 = 205
      \n(ii) The number of students who like only one subject = 52 + 59 + 55 = 166<\/p>\n

      Question 4.
      \nState the formula to find n(A \u222a B \u222a C).
      \nSolution:
      \nn( A \u222a B \u222a C) = n(A) + n(B) +n(C) – n(A \u2229 B) – (B \u2229 C) – n(A \u2229 C) + (A \u2229 B \u2229 B)<\/p>\n

      \"Samacheer<\/p>\n

      Question 5.
      \nVerify n (A \u222a B \u222a C) = n (A) + n(B) + n (C) – n(A \u2229 B) – (B \u2229 C) – n(A \u2229 C) + (A \u2229 B \u2229 C) for the following sets A = {1, 3, 5, 6, 8}, B = {3, 4, 5, 6} and C = {1, 2, 3, 6}
      \nSolution:
      \n(A \u222a B \u222a C) = {1,2, 3, 4, 5, 6, 8}
      \nn (A \u222a B \u222a C) = 7
      \nAlso, n (A) = 5, n (B) = 4, n (C) = 4,
      \nFurther, A \u2229 B = {3, 5, 6} \u21d2 n(A \u2229 B) = 3
      \nB \u2229 C = {3, 6} \u21d2 n(B \u2229 C) = 2
      \nA \u2229 C = {3, 5, 6} \u21d2 n(A \u2229 C) = 3
      \nAlso, A \u2229 B \u2229 C = {3, 6} \u21d2 n(A \u2229 B \u2229 C) = 2
      \nNow n (A \u222a B \u222a C) = n (A) + n (B) + n (C) – n(A \u2229 B) – n( B \u2229 C) – n (A \u2229 C) + n(A \u2229 B \u2229 C)
      \n7 = 5 + 4 + 4 – 3 – 2 – 3 + 2
      \n7 = 13 – 8 + 2
      \n7 = 5 + 2
      \n7 = 7
      \nThus verified<\/p>\n

      Exercise 1.7<\/span><\/p>\n

      Multiple Choice Questions
      \nQuestion 1.
      \nIf A = {5, {5, 6}, 7} which of the following is correct?
      \n(1) {5, 6} \u2208 A
      \n(2) {5} \u2208 A
      \n(3) {7} \u2208 A
      \n(4) {6} \u2208 A
      \nSolution:
      \n(1) {5, 6} \u2208 A
      \nHint: {5, 6} is an element of A.<\/p>\n

      Question 2.
      \nIf x = {a, {b, c}, d}, which of the following is a subset of X?
      \n(1) {a, b}
      \n(2) {b, c}
      \n(3) {c, d}
      \n(4) {a, d}
      \nSolution:
      \n(4) {a, d}
      \nHint: b is not an element of X. Similarly c.<\/p>\n

      Question 3.
      \nIf a finite set A has m elements, then the number of non-empty proper subset of A is
      \n(1) 2m<\/sup>
      \n(2) 2m<\/sup> – 1
      \n(3) 2m-1<\/sup>
      \n(4) 2(2m-1<\/sup> – 1)
      \nSolution:
      \n(4) 2(2m-1<\/sup> – 1)
      \nHint: P(A) = 2m Proper non empty subset = 2m – 2 = 2 (2m-1<\/sup> – 1)<\/p>\n

      Question 4.
      \nFor any three A, B and C, A – (B \u222a C) is
      \n(1) (A – B) \u222a (A – C)
      \n(2) (A – B) \u2229 (A \u222a C)
      \n(3) (A – B) \u222aC
      \n(4) A \u222a (B – C)
      \nSolution:
      \n(2) (A – B) \u2229 (A \u222a C)<\/p>\n

      Question 5.
      \nWhich of the following is true?
      \n(1) (A \u222a B) = B \u222a A
      \n(2) (A \u222a B)’ = A’ – B’
      \n(3) (A \u2229 B)’ = A’ \u2229 B’
      \n(4) A – (B \u2229 C) = (A – B) \u2229 (A – C)
      \nSolution:
      \n(1) (A \u222a B) = B \u222a A<\/p>\n

      \"Samacheer<\/p>\n

      Question 6.
      \nThe shaded region in the venn diagram is
      \n(1) A \u222a B
      \n(2) A \u2229 B
      \n(3) (A \u2229 B)’
      \n(4) (A – B) \u222a (B – A)
      \nSolution:
      \n(4) (A – B) \u222a (B – A)
      \nHint:
      \n\"Samacheer<\/p>\n","protected":false},"excerpt":{"rendered":"

      You can Download Samacheer Kalvi 9th Maths Book Solutions\u00a0Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 1 Set Language Additional Questions Text Book Activities Question 1. Discuss and give as many examples of collections from your daily …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[3],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/589"}],"collection":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/comments?post=589"}],"version-history":[{"count":1,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/589\/revisions"}],"predecessor-version":[{"id":59856,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/589\/revisions\/59856"}],"wp:attachment":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/media?parent=589"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/categories?post=589"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/tags?post=589"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}