{"id":51222,"date":"2021-05-26T12:59:31","date_gmt":"2021-05-26T07:29:31","guid":{"rendered":"https:\/\/samacheerkalviguru.com\/?p=51222"},"modified":"2021-05-26T15:44:50","modified_gmt":"2021-05-26T10:14:50","slug":"samacheer-kalvi-12th-maths-guide-chapter-4-ex-4-6-in-tamil","status":"publish","type":"post","link":"https:\/\/samacheerkalviguru.com\/samacheer-kalvi-12th-maths-guide-chapter-4-ex-4-6-in-tamil\/","title":{"rendered":"Samacheer Kalvi 12th Maths Guide Chapter 4 \u0ba8\u0bc7\u0bb0\u0bcd\u0bae\u0bbe\u0bb1\u0bc1 \u0bae\u0bc1\u0b95\u0bcd\u0b95\u0bcb\u0ba3\u0bb5\u0bbf\u0baf\u0bb2\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bc1\u0b95\u0bb3\u0bcd Ex 4.6"},"content":{"rendered":"

Tamilnadu State Board New Syllabus\u00a0Samacheer Kalvi 12th Maths Guide<\/a> Pdf Chapter 4 \u0ba8\u0bc7\u0bb0\u0bcd\u0bae\u0bbe\u0bb1\u0bc1 \u0bae\u0bc1\u0b95\u0bcd\u0b95\u0bcb\u0ba3\u0bb5\u0bbf\u0baf\u0bb2\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bc1\u0b95\u0bb3\u0bcd Ex 4.6 Textbook Questions and Answers, Notes.<\/p>\n

TN Board 12th Maths Solutions Chapter 4 \u0ba8\u0bc7\u0bb0\u0bcd\u0bae\u0bbe\u0bb1\u0bc1 \u0bae\u0bc1\u0b95\u0bcd\u0b95\u0bcb\u0ba3\u0bb5\u0bbf\u0baf\u0bb2\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bc1\u0b95\u0bb3\u0bcd Ex 4.6<\/h2>\n

\u0b95\u0bca\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f \u0ba8\u0bbe\u0ba9\u0bcd\u0b95\u0bc1 \u0bae\u0bbe\u0bb1\u0bcd\u0bb1\u0bc1 \u0bb5\u0bbf\u0b9f\u0bc8\u0b95\u0bb3\u0bbf\u0bb2\u0bbf\u0bb0\u0bc1\u0ba8\u0bcd\u0ba4\u0bc1 \u0b9a\u0bb0\u0bbf\u0baf\u0bbe\u0ba9 \u0b85\u0bb2\u0bcd\u0bb2\u0ba4\u0bc1 \u0bae\u0bbf\u0b95\u0bb5\u0bc1\u0bae\u0bcd \u0b8f\u0bb1\u0bcd\u0baa\u0bc1\u0b9f\u0bc8\u0baf \u0bb5\u0bbf\u0b9f\u0bc8\u0baf\u0bbf\u0ba9\u0bc8\u0ba4\u0bcd \u0ba4\u0bc7\u0bb0\u0bcd\u0ba8\u0bcd\u0ba4\u0bc6\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0bb5\u0bc1\u0bae\u0bcd.<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 1.
\nsin-1<\/sup> (cos x), 0 \u2264 x \u2264 \u03c0 -\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) \u03c0 – x
\n(2) x – \\(\\frac{\\pi}{2}\\)
\n(3) \\(\\frac{\\pi}{2}\\) – x
\n(4) x – \u03c0
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(3) \\(\\frac{\\pi}{2}\\) – x<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 2.
\nsin-1<\/sup>x + sin-1<\/sup>y = \\(\\frac{2 \\pi}{3}\\); \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd cos-1<\/sup> x + cos-1<\/sup> y \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) \\(\\frac{2 \\pi}{3}\\)
\n(2) \\(\\frac{\\pi}{3}\\)
\n(3) \\(\\frac{\\pi}{6}\\)
\n(4) \u03c0
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(2) \\(\\frac{\\pi}{3}\\)
\n\u0b95\u0bc1\u0bb1\u0bbf\u0baa\u0bcd\u0baa\u0bc1:
\n\u0ba8\u0bae\u0b95\u0bcd\u0b95\u0bc1 \u0ba4\u0bc6\u0bb0\u0bbf\u0baf\u0bc1\u0bae\u0bcd,
\nsin-1<\/sup>x + cos-1<\/sup>x = \\(\\frac{\\pi}{2}\\); \u0b85\u0bb2\u0bcd\u0bb2\u0ba4\u0bc1
\ncos-1<\/sup>x = \\(\\frac{\\pi}{2}\\) – sin-1<\/sup>x
\n\u2234 cos-1<\/sup> x + cos-1<\/sup> y = \\(\\frac{\\pi}{2}\\) – sin-1<\/sup>x + \\(\\frac{\\pi}{2}\\) – sin-1<\/sup>y
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 3.
\nsin-1<\/sup> \\(\\frac{3}{5}\\) – cos-1<\/sup> \\(\\frac{12}{13}\\) + sec-1<\/sup> \\(\\frac{5}{3}\\) – cosec-1<\/sup> \\(\\frac{13}{12}\\) \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) 2\u03c0
\n(2) \u03c0
\n(3) 0
\n(4) tan-1<\/sup>\\(\\frac{12}{65}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(3) 0<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 4.
\nsin-1<\/sup> x = 2 sin-1<\/sup> \u03b1 -\u0b95\u0bcd\u0b95\u0bc1 \u0b92\u0bb0\u0bc1 \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1 \u0b87\u0bb0\u0bc1\u0ba8\u0bcd\u0ba4\u0bbe\u0bb2\u0bcd, \u0baa\u0bbf\u0ba9\u0bcd\u0ba9\u0bb0\u0bcd
\n(1) |\u03b1| \u2264 \\(\\frac{1}{\\sqrt{2}}\\)
\n(2) |\u03b1| \u2265 \\(\\frac{1}{\\sqrt{2}}\\)
\n(3) |\u03b1| < \\(\\frac{1}{\\sqrt{2}}\\) (4) |\u03b1| > \\(\\frac{1}{\\sqrt{2}}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(1) |\u03b1| \u2264 \\(\\frac{1}{\\sqrt{2}}\\)
\n\u0b95\u0bc1\u0bb1\u0bbf\u0baa\u0bcd\u0baa\u0bc1:
\nsin-1<\/sup>x = 2sin-1<\/sup>\u03b1
\n\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 5.
\n\u0baa\u0bbf\u0ba9\u0bcd\u0bb5\u0bb0\u0bc1\u0bb5\u0ba9\u0bb5\u0bb1\u0bcd\u0bb1\u0bbf\u0bb2\u0bcd \u0b8e\u0bae\u0bcd\u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1\u0b95\u0bb3\u0bc1\u0b95\u0bcd\u0b95\u0bc1 sin-1<\/sup> (cos x) = \\(\\frac{\\pi}{2}\\) – x \u0b95\u0bcd\u0b95\u0bc1 \u0bae\u0bc6\u0baf\u0bcd\u0baf\u0bbe\u0b95\u0bc1\u0bae\u0bcd
\n(1) -\u03c0 \u2264 x \u2264 0
\n(2) 0 \u2264 x \u2264 \u03c0
\n(3) –\\(\\frac{\\pi}{2}\\) \u2264 x \u2264 \\(\\frac{\\pi}{2}\\)
\n(4) –\\(\\frac{\\pi}{4}\\) \u2264 x \u2264 \\(\\frac{3 \\pi}{4}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(2) 0 \u2264 x \u2264 \u03c0<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 6.
\nsin-1<\/sup> x + sin-1<\/sup> y + sin-1<\/sup> z = \\(\\frac{3 \\pi}{2}\\) \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd x2017<\/sup> + y2018<\/sup> + z2019<\/sup> – \\(\\frac{9}{x^{101}+y^{101}+z^{101}}\\) – \u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) 0
\n(2) 1
\n(3) 2
\n(4) 3
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(1) 0<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 7.
\n\u0b9a\u0bbf\u0bb2 x \u2208 R-\u0b95\u0bcd\u0b95\u0bc1 cot-1<\/sup>x = \\(\\frac{2 \\pi}{5}\\) \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd tan-1<\/sup>x-\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) – \\(\\frac{\\pi}{10}\\)
\n(2) \\(\\frac{\\pi}{5}\\)
\n(3) \\(\\frac{\\pi}{10}\\)
\n(4) –\\(\\frac{\\pi}{5}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(3) \\(\\frac{\\pi}{10}\\)<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 8.
\nf (x) = sin-1<\/sup>\\(\\sqrt{x-1}\\) \u0b8e\u0ba9 \u0bb5\u0bb0\u0bc8\u0baf\u0bb1\u0bc1\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bc1\u0bae\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bbf\u0ba9\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0b95\u0bae\u0bcd
\n(1) [1, 2]
\n(2) [-1, 1]
\n(3) [0, 1]
\n(4) [-1, 0]
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(1) [1, 2]
\n\u0b95\u0bc1\u0bb1\u0bbf\u0baa\u0bcd\u0baa\u0bc1:
\n-1 \u2264 x – 1 \u2264 1 \u0bae\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd x – 1 \u2265 0
\n\u21d2 0 \u2264 x – 1 \u2264 1 \u21d2 1 \u2264 x \u2264 2<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 9.
\nx = \\(\\frac{1}{5}\\) \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd , cos(cos-1<\/sup> x + 2sin-1<\/sup> x)-\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) –\\(\\sqrt{\\frac{24}{25}}\\)
\n(2) \\(\\sqrt{\\frac{24}{25}}\\)
\n(3) \\(\\frac{1}{5}\\)
\n(4) –\\(\\frac{1}{5}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(4) –\\(\\frac{1}{5}\\)
\n\u0b95\u0bc1\u0bb1\u0bbf\u0baa\u0bcd\u0baa\u0bc1:
\ncos (cos-1<\/sup>x + sin-1<\/sup>x + sin-1<\/sup>x)
\n\u21d2 cos (\\(\\frac{\\pi}{2}\\) + sin-1<\/sup>x) = – sin (sin-1<\/sup>x) = -x = –\\(\\frac{1}{5}\\)
\n[\u2235 cos-1<\/sup>x + sin-1<\/sup>x = \\(\\frac{\\pi}{2}\\)]<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 10.
\ntan-1<\/sup> \\(\\left(\\frac{1}{4}\\right)\\) + tan-1<\/sup> \\(\\left(\\frac{2}{9}\\right)\\) \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0bbf\u0ba9\u0bcd \u0b9a\u0bae\u0bae\u0bcd
\n(1) \\(\\frac{1}{2}\\)cos-1<\/sup>\\(\\left(\\frac{3}{5}\\right)\\)
\n(2) \\(\\frac{1}{2}\\)sin-1<\/sup>\\(\\left(\\frac{3}{5}\\right)\\)
\n(3) \\(\\frac{1}{2}\\)tan-1<\/sup>\\(\\left(\\frac{3}{5}\\right)\\)
\n(4) \\(\\frac{1}{2}\\)tan-1<\/sup>\\(\\left(\\frac{1}{2}\\right)\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(4) \\(\\frac{1}{2}\\)tan-1<\/sup>\\(\\left(\\frac{1}{2}\\right)\\)
\n\u0b95\u0bc1\u0bb1\u0bbf\u0baa\u0bcd\u0baa\u0bc1:
\n\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 11.
\n\u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bc1 f(x) = sin-1<\/sup> x (x2<\/sup> \u2013 3) x \u0b87\u0bb0\u0bc1\u0b95\u0bcd\u0b95\u0bc1\u0bae\u0bcd \u0b87\u0b9f\u0bc8\u0bb5\u0bc6\u0bb3\u0bbf
\n(1) [\u20131, 1]
\n(2) [\\(\\sqrt{2}\\), 2]
\n(3) [-2, –\\(\\sqrt{2}\\)] \u222a [ \\(\\sqrt{2}\\), 2]
\n(4) [-2, –\\(\\sqrt{2}\\)]
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(3) [-2, –\\(\\sqrt{2}\\)] \u222a [ \\(\\sqrt{2}\\), 2]
\n\u0b95\u0bc1\u0bb1\u0bbf\u0baa\u0bcd\u0baa\u0bc1:
\n-1 \u2264 x2<\/sup> – 3 \u2264 1
\n\u21d2 2 \u2264 x2<\/sup> \u2264 4
\n\u2234 2 \u2264 x2<\/sup> \u0bae\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd x2<\/sup> \u2264 4<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 12.
\ncot-1<\/sup> 2 \u0bae\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd cot-1<\/sup> 3 \u0b86\u0b95\u0bbf\u0baf\u0ba9 \u0b92\u0bb0\u0bc1 \u0bae\u0bc1\u0b95\u0bcd\u0b95\u0bcb\u0ba3\u0ba4\u0bcd\u0ba4\u0bbf\u0ba9\u0bcd \u0b87\u0bb0\u0bc1 \u0b95\u0bcb\u0ba3\u0b99\u0bcd\u0b95\u0bb3\u0bcd \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, \u0bae\u0bc2\u0ba9\u0bcd\u0bb1\u0bbe\u0bb5\u0ba4\u0bc1 \u0b95\u0bcb\u0ba3\u0bae\u0bbe\u0ba9\u0ba4\u0bc1
\n(1) \\(\\frac{\\pi}{4}\\)
\n(2) \\(\\frac{3 \\pi}{4}\\)
\n(3) \\(\\frac{\\pi}{6}\\)
\n(4) \\(\\frac{\\pi}{3}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(2) \\(\\frac{3 \\pi}{4}\\)<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 13.
\n\"Samacheer
\n(1) x2<\/sup> – x – 6 = 0
\n(2) x2<\/sup> – x – 12 = 0
\n(3) x2<\/sup> + x – 12 = 0
\n(4) x2<\/sup> + x – 6 = 0
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(2) x2<\/sup> – x – 12 = 0<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 14.
\nsin-1<\/sup> (2 cos2<\/sup>x – 1) + cos-1<\/sup> (1 – 2sin2<\/sup> x) =
\n(1) \\(\\frac{\\pi}{2}\\)
\n(2) \\(\\frac{\\pi}{3}\\)
\n(3) \\(\\frac{\\pi}{4}\\)
\n(4) \\(\\frac{\\pi}{6}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(1) \\(\\frac{\\pi}{2}\\)<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 15.
\ncot-1<\/sup> \\((\\sqrt{\\sin \\alpha})\\) + tan-1<\/sup> \\((\\sqrt{\\sin \\alpha})\\) = u \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd,
\ncos 2u \u0baa\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) tan2<\/sup>\u03b1
\n(2) 0
\n(3) -1
\n(4) tan 2\u03b1
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(3) -1<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 16.
\n|x| \u2264 1, \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, 2tan-1<\/sup> x – sin-1<\/sup> \\(\\frac{2 x}{1+x^{2}}\\) \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0bb1\u0bcd\u0b95\u0bc1 \u0b9a\u0bae\u0bae\u0bcd
\n(1) tan-1<\/sup>x
\n(2) sin-1<\/sup>x
\n(3) 0
\n(4) \u03c0
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(3) 0<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 17.
\ntan-1<\/sup>x – cot-1<\/sup>x = tan-1<\/sup>\\(\\left(\\frac{1}{\\sqrt{3}}\\right)\\) \u0b8e\u0ba9\u0bcd\u0bb1
\n\u0b9a\u0bae\u0ba9\u0bcd\u0baa\u0bbe\u0b9f\u0bcd\u0b9f\u0bbf\u0bb1\u0bcd\u0b95\u0bc1
\n(1) \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1 \u0b87\u0bb2\u0bcd\u0bb2\u0bc8
\n(2) \u0b92\u0bb0\u0bc7\u0baf\u0bca\u0bb0\u0bc1 \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1
\n(3) \u0b87\u0bb0\u0bc1 \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1\u0b95\u0bb3\u0bcd
\n(4) \u0b8e\u0ba3\u0bcd\u0ba3 \u0bb1\u0bcd\u0bb1\u0ba4\u0bcd \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1\u0b95\u0bb3\u0bcd
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(2) \u0b92\u0bb0\u0bc7\u0baf\u0bca\u0bb0\u0bc1 \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1 .<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 18.
\nsin-1<\/sup>x+ cos-1<\/sup> \\(\\) = \\(\\) \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd x-\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) \\(\\frac{1}{2}\\)
\n(2) \\(\\frac{1}{\\sqrt{5}}\\)
\n(3) \\(\\frac{2}{\\sqrt{5}}\\)
\n(4) \\(\\frac{\\sqrt{3}}{2}\\)
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(2) \\(\\frac{1}{\\sqrt{5}}\\)<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 19.
\nsin-1<\/sup> \\(\\frac{x}{5}\\) + cos-1<\/sup> \\(\\frac{5}{4}\\) = \\(\\frac{\\pi}{2}\\) \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, x-\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n(1) 4
\n(2) 5
\n(3) 2
\n(4) 3
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(4) 3<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 20.
\n|x| < 1 \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, sin(tan-1 x) -\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc1
\n\"Samacheer
\n\u0bb5\u0bbf\u0b9f\u0bc8:
\n(4) \\(\\frac{x}{\\sqrt{1+x^{2}}}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

Tamilnadu State Board New Syllabus\u00a0Samacheer Kalvi 12th Maths Guide Pdf Chapter 4 \u0ba8\u0bc7\u0bb0\u0bcd\u0bae\u0bbe\u0bb1\u0bc1 \u0bae\u0bc1\u0b95\u0bcd\u0b95\u0bcb\u0ba3\u0bb5\u0bbf\u0baf\u0bb2\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bc1\u0b95\u0bb3\u0bcd Ex 4.6 Textbook Questions and Answers, Notes. TN Board 12th Maths Solutions Chapter 4 \u0ba8\u0bc7\u0bb0\u0bcd\u0bae\u0bbe\u0bb1\u0bc1 \u0bae\u0bc1\u0b95\u0bcd\u0b95\u0bcb\u0ba3\u0bb5\u0bbf\u0baf\u0bb2\u0bcd \u0b9a\u0bbe\u0bb0\u0bcd\u0baa\u0bc1\u0b95\u0bb3\u0bcd Ex 4.6 \u0b95\u0bca\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f \u0ba8\u0bbe\u0ba9\u0bcd\u0b95\u0bc1 \u0bae\u0bbe\u0bb1\u0bcd\u0bb1\u0bc1 \u0bb5\u0bbf\u0b9f\u0bc8\u0b95\u0bb3\u0bbf\u0bb2\u0bbf\u0bb0\u0bc1\u0ba8\u0bcd\u0ba4\u0bc1 \u0b9a\u0bb0\u0bbf\u0baf\u0bbe\u0ba9 \u0b85\u0bb2\u0bcd\u0bb2\u0ba4\u0bc1 \u0bae\u0bbf\u0b95\u0bb5\u0bc1\u0bae\u0bcd \u0b8f\u0bb1\u0bcd\u0baa\u0bc1\u0b9f\u0bc8\u0baf \u0bb5\u0bbf\u0b9f\u0bc8\u0baf\u0bbf\u0ba9\u0bc8\u0ba4\u0bcd \u0ba4\u0bc7\u0bb0\u0bcd\u0ba8\u0bcd\u0ba4\u0bc6\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0bb5\u0bc1\u0bae\u0bcd. \u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 1. sin-1 (cos x), 0 \u2264 x \u2264 \u03c0 -\u0ba9\u0bcd …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[8],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/51222"}],"collection":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/comments?post=51222"}],"version-history":[{"count":0,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/51222\/revisions"}],"wp:attachment":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/media?parent=51222"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/categories?post=51222"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/tags?post=51222"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}