{"id":3751,"date":"2023-12-10T12:25:24","date_gmt":"2023-12-10T06:55:24","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=3751"},"modified":"2023-12-11T17:51:58","modified_gmt":"2023-12-11T12:21:58","slug":"samacheer-kalvi-8th-maths-solutions-term-2-chapter-2-intext-questions","status":"publish","type":"post","link":"https:\/\/samacheerkalviguru.com\/samacheer-kalvi-8th-maths-solutions-term-2-chapter-2-intext-questions\/","title":{"rendered":"Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 2 Algebra Intext Questions"},"content":{"rendered":"

Students can Download Maths Chapter 2 Algebra Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions<\/a> Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 2 Algebra Intext Questions<\/h2>\n

Exercise 2.1
\nTry These (Text book page no. 32)<\/span><\/p>\n

Question 1.
\nIdentify which among the following are linear equations.<\/p>\n

    \n
  1. 2 + x = 19 – Linear as degree of the variable x is 1<\/li>\n
  2. 7x2<\/sup> – 5 = 3 – not linear as highest degree of x is 2<\/li>\n
  3. 4p3<\/sup> = 12 – not linear as highest degree ofp is 3<\/li>\n
  4. 6m + 2 – Linear, but not an equation<\/li>\n
  5. n = 10 – Linear equation as degree of n is 1<\/li>\n
  6. 7k – 12= 0 – Linear equation as degree of Hs 1<\/li>\n
  7. \\(\\frac{6x}{8}\\) + y = 1 – Linear equation as degree ofx & y is 1<\/li>\n
  8. 5 + y = 3x – Linear equation as degree ofy & x is 1<\/li>\n
  9. 10p + 2q = 3 – Linear equation a& degree ofp & q is 1<\/li>\n
  10. x2<\/sup> – 2x-4 – not linear equation as highest degree of x is 2<\/li>\n<\/ol>\n

    \"Samacheer<\/p>\n

    Think (Text book page no. 32)<\/span><\/p>\n

    Question 1.
    \nIs t(t – 5)= =10 a linear equation? Why?
    \nSolution:
    \nt(t – 5) = 10
    \n= t x t – 5 x t = 10
    \n= t2<\/sup> – 5t = 10
    \nThis is not a linear equation as the highest degree of the variable ‘t’ is 2<\/p>\n

    Question 2.
    \nIs x2<\/sup> = 2x, a linear equation? Why?
    \nSolution:
    \nx2<\/sup> = 2x
    \n= x2<\/sup> – 2x = 0
    \nThis is not a linear equations as the highest degree of the variable ‘x’ is 2<\/p>\n

    Try These (Text book page no. 33)<\/span><\/p>\n

    Convert the following statements into linear equations:<\/p>\n

    Question 1.
    \nOn subtracting 8 from the product of 5 and a number, I get 32.
    \nSolution:
    \nConvert to linear equations:
    \nGiven that on subtracting 8 from product of 5 and a, we get 32
    \n5 \u00d7 x – 8 = 32
    \n5x – 8 = 32<\/p>\n

    \"Samacheer<\/p>\n

    Question 2.
    \nThe sum of three consecutive integers is 78.
    \nSolution:
    \nSum of 3 consecutive integers is 78
    \nLet 1st integer be ‘x’
    \n\u2234 x + (x + 1) + (x + 2) = 78
    \n\u2234 x + x + 1 + x + 2 = 78
    \n3x + 3 = 78<\/p>\n

    Question 3.
    \nPeter had a Two hundred rupee note. After buying 7 copies of a book he was left with \u20b9 60.
    \nSolution:
    \nLet cost of one book be ‘x’
    \n\u2234 Given that 200 – 7 \u00d7 x = 60
    \n\u2234 200 – 7x = 60<\/p>\n

    Question 4.
    \nThe base angles of an isosceles triangle are equal and the vertex angle measures 80\u00b0.
    \nSolution:
    \nLet base angles each be equal to x & vertex bottom angle is 80\u00b0. Applying triangle
    \nproperty, sum of all angles is 180\u00b0
    \n\u2234 x + x + 80 = 180\u00b0
    \n2x + 80 = 180\u00b0<\/p>\n

    \"Samacheer<\/p>\n

    Question 5.
    \nIn a triangle ABC, \u2220A is 10\u00b0 more than \u2220B. Also \u2220C is three times \u2220A. Express the equation in terms of angle B
    \nSolution:
    \nLet \u2220B = b
    \nGiven \u2220A = 10\u00b0 + \u2220B = 10 + b
    \nAlso given that \u2220C = 3 x \u2220A = 3 x (10 + 6) = 30 + 3b
    \nSum of the angles = 180\u00b0
    \n\u2220A + \u2220B + \u2220C = 180\u00b0
    \n10 + b + b + 30 + 3b = 180\u00b0
    \n\u2234 5b + 40 = 180\u00b0<\/p>\n

    Think (Text book page no. 34)<\/span><\/p>\n

    Question 1.
    \nCan you get more than one solution for a linear equation?
    \nSolution:
    \nYes, we can get. Consider the below line or equation
    \nx + y = 5
    \nhere, when x = 1, y = 4
    \nwhen x = 2, y = 2
    \nx = 3, y = 2
    \nx = 4, y = 1
    \nHence, we get multiple solutions for the same linear equation.<\/p>\n

    Think (Text book page no. 35)<\/span><\/p>\n

    Question 1.
    \n\u201cAn equation is multiplied or divided by a non zero number on either side.\u201d Will there be any change in the solution?
    \nSolution:
    \nNot be any change in the solution<\/p>\n

    \"Samacheer<\/p>\n

    Question 2.
    \n\u201cAn equation is multiplied or divided by two different numbers on either side\u201d. What will happen to the equation?
    \nSolution:
    \nWhen an equation is multiplied or divided by 2 different numbers on either side, there will be a change in the equation & accordingly, solution will also change.<\/p>\n

    Exercise 2.2
    \nThink (Text book page no. 37)<\/span><\/p>\n

    Question 1.
    \nSuppose we take the second piece to be x and the first piece to be (200 – x), how will the steps vary. Will the answer be different?
    \nSolution:
    \nLet 2nd piece be V & 1st piece is 200 – x
    \nGiven that 1st piece is 40 cm smaller than hence the other piece
    \n\u2234 200 – x = 2 \u00d7 x – 40
    \n\"Samacheer
    \n200 + 40 = 2x + x
    \n240 = 3x
    \n\u2234 x = \\(\\frac{240}{3}\\) = 80
    \n\u2234 1st piece = 200 – x = 200 – 80 = 120 cm
    \n2nd piece = x = 80 cm
    \nThe answer will not change<\/p>\n

    Exercise 2.3
    \nThink (Text book page no. 43)<\/span><\/p>\n

    Question 1.
    \nIf instead of (4, 3), we write (3, 4) and try to mark it, will it represent \u2018M\u2019 again?
    \nSolution:
    \nLet 3, 4 be M, when we mark, we find that it is a different point and not ‘M’<\/p>\n

    Try These (Text book page no. 45)<\/span><\/p>\n

    Question 1.
    \nComplete the table given below.
    \n\"Samacheer
    \nSolution:
    \n\"\"<\/p>\n

    Question 2.
    \nWrite the coordinates of the points marked in the following figure
    \n\"Samacheer<\/p>\n

      \n
    • A – (-3, 2)<\/li>\n
    • B – (5, 2)<\/li>\n
    • C – (5, -3)<\/li>\n
    • D – (-3, 3)<\/li>\n
    • E – (-1,4)<\/li>\n
    • F – (1, 2)<\/li>\n
    • G – (7, 4)<\/li>\n
    • H – (0, 2)<\/li>\n
    • i – (o, 3)<\/li>\n
    • J – (-3, 0)<\/li>\n
    • K – (5, 0)<\/li>\n
    • L – (-1, 0)<\/li>\n
    • M – (-2, 0)<\/li>\n
    • N – (-2, -1)<\/li>\n
    • O – (0, 0)<\/li>\n
    • P – (-1, -1)<\/li>\n
    • Q – (1, -1)<\/li>\n
    • R – (2, -1)<\/li>\n
    • S – (0, -3)<\/li>\n
    • T – (7, 0)<\/li>\n
    • U – (7, -2)<\/li>\n<\/ul>\n

      Exercise 2.4
      \nThink (Text book page no. 49)<\/span><\/p>\n

      Question 1.
      \nWhich of the points (5, -10) (0, 5) (5, 20) lie on the straight line X = 5?
      \nSolution:
      \nAll points on the line X = 5 will have X – coordinate as 5.
      \nTherefore, any point with X – coordinate as 5 will lie on X = 5 line.
      \nHence the points (5, – 10) & (5,20) will lie on X = 5<\/p>\n

      Think (Text book page no. 54)<\/span><\/p>\n

      \"Samacheer<\/p>\n

      Question 1.
      \nWhy is it given that the speed is \u2018constant\u2019? If the speed is not constant, will the graph be the same? The graph is named as y = 80 x algebraically. Why?
      \nSolution:
      \n\"Samacheer
      \nor in other words, the slope of a line in a distance – time graph. We observe that the slope of the graph is constant hence, speed is constant. If the speed is not constant, the graph will be different as slope of the line would change.<\/p>\n","protected":false},"excerpt":{"rendered":"

      Students can Download Maths Chapter 2 Algebra Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 2 Algebra Intext Questions Exercise 2.1 Try …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[4],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/3751"}],"collection":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/comments?post=3751"}],"version-history":[{"count":2,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/3751\/revisions"}],"predecessor-version":[{"id":60097,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/3751\/revisions\/60097"}],"wp:attachment":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/media?parent=3751"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/categories?post=3751"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/tags?post=3751"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}