{"id":2932,"date":"2023-12-18T11:07:17","date_gmt":"2023-12-18T05:37:17","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=2932"},"modified":"2023-12-19T17:50:46","modified_gmt":"2023-12-19T12:20:46","slug":"samacheer-kalvi-7th-maths-term-2-chapter-1-additional-questions","status":"publish","type":"post","link":"https:\/\/samacheerkalviguru.com\/samacheer-kalvi-7th-maths-term-2-chapter-1-additional-questions\/","title":{"rendered":"Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Additional Questions"},"content":{"rendered":"

Students can Download Maths Chapter 1 Number System Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions<\/a> Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Additional Questions<\/h2>\n

Additional Questions and Answers<\/span><\/p>\n

Exercise 1.1<\/span><\/p>\n

Question 1.
\nExpress as rupees using decimals.
\n(i) 4 paise
\n(ii) 4 rupees 4 paise
\n(iii) 44 rupees 44 paise
\n(iv) 50 paise
\n(v) 625 paise
\nSolution:
\nWe know that 100 paise = \u20b9 1
\n1 paise = \u20b9 \\(\\frac { 1 }{ 100 } \\)
\n(i) 4 paise = \u20b9 4 \u00d7 \\(\\frac { 1 }{ 100 } \\) = \u20b9 \\(\\frac { 4 }{ 100 } \\) = \u20b9 0.04
\n(ii) 4 rupees 4 paise = \u20b9 4 + \u20b9 0.04 = \u20b9 4.04
\n(iii) 44 rupees 4 paise = \u20b9 44 + 44 paise = \u20b9 44 + \u20b9 \\(\\frac { 44 }{ 100 } \\) = \u20b9 44 + \u20b9 0.44 = \u20b9 44.44
\n(iv) 625 paise = 600 paise + 25 paise = \u20b9 6 + \u20b9 \\(\\frac { 25 }{ 100 } \\) = \u20b9 6 + \u20b9 0.25 = \u20b9 6.25<\/p>\n

\"Samacheer<\/p>\n

Question 2.
\nExpress 7 cm in metre and kilometer.
\nSolution:
\n7 cm = \\(\\frac { 7 }{ 100 } \\) m = 0.07 m
\n7 cm = \\(\\frac { 7 }{ 10000 } \\) km = 0.00007 km<\/p>\n

Question 3.
\nWrite the following decimal numbers in the expanded form.
\n(i) 30.04
\n(ii) 3.04
\n(iii) 300.04
\nSolution:
\n(i) 30.04 = 3 \u00d7 10 + 0 \u00d7 1 + 0 \u00d7 \\(\\frac { 1 }{ 10 } \\) + 4 \u00d7 \\(\\frac { 1 }{ 100 } \\) = 3 \u00d7 10 + \\(\\frac { 4 }{ 100 } \\)
\n(ii) 3.04 = 3 \u00d7 1 + 0 \u00d7 \\(\\frac { 1 }{ 10 } \\) + 4 \u00d7 \\(\\frac { 1 }{ 100 } \\) = 3 \u00d7 1 + \\(\\frac { 4 }{ 100 } \\)
\n(iii) 300.04 = 3 \u00d7 100 + 0 \u00d7 10 + 0 \u00d7 1 + 0 \u00d7 \\(\\frac { 1 }{ 10 } \\) + 4 \u00d7 \\(\\frac { 1 }{ 100 } \\) = 3 \u00d7 100 + \\(\\frac { 4 }{ 100 } \\) = 3 \u00d7 100 + \\(\\frac { 4 }{ 100 } \\)<\/p>\n

Question 4.
\nWrite the place value of 2 in the following decimal numbers.
\n(i) 2.47
\n(ii) 26.89
\n(iii) 36.28
\nSolution:
\n(i) 2.47 Place value of 2 in 2.47 is ones.
\n(ii) 26.89 Place value of 2 in 26.89 is Tens.
\n(iii) 36.28 Place value of 2 in 36.28 is tenths<\/p>\n

\"Samacheer<\/p>\n

Exercise 1.2<\/span><\/p>\n

Question 1.
\nExplain the following as fractions.
\n(i) Ajar containing 3.6 litres of milk.
\n(ii) A cup containing 9.63 mg of medicine.
\nSolution:
\n(i) 3.6 = 3 + \\(\\frac { 6 }{ 10 } \\) = 3 + \\(\\frac { 3 }{ 5 } \\) = 3 \\(\\frac { 3 }{ 5 } \\) litre of milk
\n(ii) 9.63 = 9 + \\(\\frac { 6 }{ 10 } \\) + \\(\\frac { 3 }{ 100 } \\) = \\(\\frac { 900+60+3 }{ 100 } \\) = \\(\\frac { 963 }{ 100 } \\) mg of medicine<\/p>\n

Question 2.
\nConvert into decimal.
\n(i) Three hundred three and nine hundredths.
\n(ii) Six and fifty five thousands
\nSolution:
\n(i) Three hundred three and nine hundredths
\n= 303 + \\(\\frac { 9 }{ 100 } \\) = 303 + 0 \u00d7 \\(\\frac { 1 }{ 10 } \\) + 9 \u00d7 \\(\\frac { 1 }{ 100 } \\) = 303.09<\/p>\n

(ii) Six and fifty five thousands
\n6 + \\(\\frac { 55 }{ 100 } \\) = 6 + \\(\\frac { 5 }{ 100 } \\) + \\(\\frac { 5 }{ 1000 } \\) = 6 + \\(\\frac { 0 }{ 10 } \\) + \\(\\frac { 5 }{ 100 } \\) + \\(\\frac { 5 }{ 1000 } \\) = 6.055<\/p>\n

Question 3.
\nFind the decimal form of (i) 194 + 20 + 3 + \\(\\frac { 7 }{ 10 } \\) + \\(\\frac { 2 }{ 100 } \\)
\n(ii) 111 + 11 + 1 + \\(\\frac { 1 }{ 10 } \\) + \\(\\frac { 1 }{ 1000 } \\)
\nSolution:
\n(i) 194 + 20 + 3 + \\(\\frac { 7 }{ 10 } \\) + \\(\\frac { 2 }{ 100 } \\) = 217 + 7 \u00d7 \\(\\frac { 1 }{ 10 } \\) + 2 \u00d7 \\(\\frac { 1 }{ 100 } \\) = 217.72<\/p>\n

(ii) 111 + 11 + 1 + \\(\\frac { 1 }{ 10 } \\) + \\(\\frac { 1 }{ 1000 } \\) = 123 + 1 \u00d7 \\(\\frac { 1 }{ 10 } \\) + 0 \u00d7 \\(\\frac { 1 }{ 100 } \\) + 1 \u00d7 \\(\\frac { 1 }{ 1000 } \\) = 123.101<\/p>\n

\"Samacheer<\/p>\n

Exercise 1.3<\/span><\/p>\n

Question 1.
\nMaya bought 5 kg 300 g bananas and 3 kg 250 kg oranges. Diya bought 4 kg 800 g apples and 4 kg 150 g of mangoes. Who bought more fruits.
\nSolution:
\nTotal fruits bought by Maya = 5 kg 300 g + 3 kg 250 g = 8 kg 550 g = 8.550 kg
\nTotal fruits Diya bought = 4 kg 800 g + 4 kg 150 g = 8 kg 950 g = 8.950 kg
\nComparing the whole number parts, they are equal.
\nComparing thet tenths place we get 9 > 5.
\n\u2234 8.950 kg > 8.550 kg
\n\u2234 Diya bought more fruits.<\/p>\n

Question 2.
\nWhich is greater 28 km or 42.6 km.
\nSolution:
\nComparing the whole number part 42 > 28.
\n42.6 km is greater than 28 km.<\/p>\n

\"Samacheer<\/p>\n

Exercise 1.4<\/span><\/p>\n

Question 1.
\nShow that the following numbers in a number line.
\n(i) 0.2
\n(ii) 1.8
\n(iii) 1.1
\n(iv) 2.6
\nSolution:
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

Question 2.
\nWrite the decimal numbers represented by the points A, B, C, D, E and F.
\nSolution:
\n\"Samacheer
\nA (0.5); B (1.2); C (2.3); D (2.8); E (3.4); F (3.9)<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Maths Chapter 1 Number System Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Additional Questions Additional …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[5],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/2932"}],"collection":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/comments?post=2932"}],"version-history":[{"count":1,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/2932\/revisions"}],"predecessor-version":[{"id":60174,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/2932\/revisions\/60174"}],"wp:attachment":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/media?parent=2932"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/categories?post=2932"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/tags?post=2932"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}