{"id":168,"date":"2021-03-26T09:03:48","date_gmt":"2021-03-26T03:33:48","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=168"},"modified":"2021-03-26T10:12:53","modified_gmt":"2021-03-26T04:42:53","slug":"samacheer-kalvi-10th-maths-chapter-8-ex-8-4","status":"publish","type":"post","link":"https:\/\/samacheerkalviguru.com\/samacheer-kalvi-10th-maths-chapter-8-ex-8-4\/","title":{"rendered":"Samacheer Kalvi 10th Maths Solutions Chapter 8 Statistics and Probability Ex 8.4"},"content":{"rendered":"

You can Download Samacheer Kalvi 10th Maths Book Solutions<\/a> Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 8 Statistics and Probability Ex 8.4<\/h2>\n

10th Maths Exercise 8.4 Samacheer Kalvi Question 1.<\/strong>
\nIf P(A) = \\(\\frac{2}{3}\\), P(B) = \\(\\frac{2}{5}\\), P(A\u222aB) = 13 then find P(A\u2229B).
\nSolution:
\nP(A) = \\(\\frac{2}{3}\\), P(B) = \\(\\frac{2}{5}\\), P(A\u222aB) = \\(\\frac{1}{3}\\)
\nP(A \u2229 B) = P(A) + P(B) – P(A\u222aB)
\n\"10th<\/p>\n

Ex 8.4 Class 10 Samacheer Question 2.<\/strong>
\nA and B are two events such that, P(A) = 0.42, P(B) = 0.48, and P(A \u2229 B) = 0.16. Find
\n(i) P(not A)
\n(it) P(not B)
\n(iii) P(A or B)
\nAnswer:
\n(i) P(not A) = 1 – P (A) = 1 – 0.42 = 0.58
\n(ii) P(not B) = 1 – P(B) = 1 – 0.48 = 0.52
\n(iii) P(A or B) = P(A) + P(B) – P(A \u2229 B) = 0.42 + 0.48 – 0.16 = 0.90 – 0.16 = 0.74<\/p>\n

Exercise 8.4 Class 10 Samacheer Question 3.<\/strong>
\nIf A and B are two mutually exclusive events of a random experiment and P(not A) = 0.45, P(A\u222aB) = 0.65, then find P(B).
\nSolution:
\nA and B are two mutually exclusive events of a random experiment.
\nP(not A) = 0.45,
\nP(A) = 1 – P(not A)
\nP(A\u222aB) = 0.65 = 1 – 0.45 = 0.55
\nP(A\u222aB) = P(A) + P(B) = 0.65
\n0.55 + P(B) = 0.65
\nP(B) = 0.65 – 0.55
\n= 0.10<\/p>\n

10th Maths Exercise 8.4 Question 4.<\/strong>
\nThe probability that atleast one of A and B occur is 0.6. If A and B occur simultaneously with probability 0.2, then find P(\\(\\bar{A}\\)) + P(\\(\\bar{B}\\)).
\nAnswer:
\nHere P (A \u222a B) = 0.6, P (A \u2229 B) = 0.2
\nP (A \u222a B) = P (A) + P (B) – P (A \u2229 B)
\n0.6 = P (A) + P (B) – 0.2
\nP(A) + P(B) = 0.8
\nP(\\(\\bar{A}\\)) + P(\\(\\bar{B}\\)) = 1 – P(A) + 1 – P(B)
\n= 2 – [P(A) + P(B)]
\n= 2 – 0.8
\n= 1.2<\/p>\n

10th Maths 8.4 Solutions Question 5.<\/strong>
\nThe probability of happening of an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then find the probability that neither A nor B happen.
\nSolution:
\nP(A) = 0.5 Since A and B are mutually inclusive events
\nP(B) = 0.3 events.
\nP(\\(\\overline{\\mathbf{A}}\\))\u222aP(\\(\\overline{\\mathbf{B}}\\)) = 1 – [P(A) + P(B)]
\n= 1 – [0.5 + 0.3] = 0.2<\/p>\n

10th Maths Probability Exercise 8.4 Question 6.<\/strong>
\nTwo dice are rolled once. Find the probability of getting an even number on the first die or a total of face sum 8.
\nSolution:
\nTwo dice rolled once.
\n\"Ex
\n\"Exercise<\/p>\n

10th Maths Ex 8.4 Question 7.<\/strong>
\nFrom a well-shuffled pack of 52 cards, a card is drawn at random. Find the probability of it being either a red king or a black queen.
\nSolution:
\nn(S) = 52
\nNo. of Red cards = 26,
\nRed king cards = 2
\nNo. of Black cards = 26,
\nBlack queen cards = 2
\nNo. of red king cards = n(K) = 2
\n\"10th
\n\u2234 The probability of being either a red king or a black queen = \\(\\frac{1}{13}\\).<\/p>\n

10th Maths Exercise 8.4 Solution Question 8.<\/strong>
\nA box contains cards numbered 3, 5, 7, 9,… 35, 37. A card is drawn at random from the box. Find the probability that the drawn card has either multiples of 7 or a prime number.
\nSolution:
\nS = {3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37}
\nn(S) = 18
\nMultiplies of seven cards (A) = {7, 21, 35}
\n= n(A) = 3
\n\"10th
\nLet the prime number cards B
\nB = {3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37}
\nn(B) = 11
\n\"10th<\/p>\n

10th Maths Exercise 8.4 In Tamil Question 9.<\/strong>
\nThree unbiased coins are tossed once. Find the probability of getting at most 2 tails or at least 2 heads.
\nSolution:
\nWhen we toss three coins, the sample space S = {HHH, TTT, HTT, THH, HHT, TTH, HTH, THT}
\nn(S) = 8
\nEvent of getting at most 2 tails be A.
\n\u2234 A = { HHH, HTT, THH, HHT, TTH, HTH, THT}
\n\"10th<\/p>\n

10th Maths Statistics And Probability Question 10.<\/strong>
\nThe probability that a person will get an electrification contract is the probability that he will not get plumbing contract is \\(\\frac{3}{5}\\). The probability of getting at least one contract is \\(\\frac{5}{8}\\). What is the probability that he will get both?
\nSolution:
\n\"10th
\n\"10th<\/p>\n

10th Maths 8.4 Question 11.<\/strong>
\nIn a town of 8000 people, 1300 are over 50 years and 3000 are females. It is known that 30% of the females are over 50 years. What is the probability that a chosen individual from the town is either a female or over 50 years ?
\nSolution:
\n\"10th<\/p>\n

10th Exercise 8.4 Question 12.<\/strong>
\nA coin is tossed thrice. Find the probability of getting exactly two heads or at least one tail or two consecutive heads.
\nSolution:
\nThree coins tossed simultaneously.
\nS = { HHH, TTT, HHT, TTH, HTH, THT, HTT, THH}
\nn(S) = 8
\nHappening of getting exactly two heads be A.
\nA= {HHT, HTH, THH}
\nn(A) = 3
\n\"10th
\nEvent of getting at least one tail be B.
\n\u2234 B = {TTT, HHT, TTH, HTH, THT, HTT, THH}
\n\"10th
\n\"Samacheer<\/p>\n

Samacheer Kalvi Guru 10th Maths Question 13.<\/strong>
\nIf A, B, C are any three events such that probability of B is twice as that of probability of A and probability of C is thrice as that of probability of A and if P(A\u2229B) = \\(\\frac{1}{6}\\), P(B\u2229C) = \\(\\frac{1}{4}\\), P(A\u2229C) = \\(\\frac{1}{8}\\), \\(\\mathbf{P}(\\mathbf{A} \\cup \\mathbf{B} \\cup \\mathbf{C})=\\frac{9}{10}, \\mathbf{P}(\\mathbf{A} \\cap \\mathbf{B} \\cap \\mathbf{C})=\\frac{1}{15}\\), then find P(A), P(B) and P(C)?
\nSolution:
\nP(B) = 2P(A)
\nP(C) = 3P(A)
\n\"10th
\n\"10th<\/p>\n

10th Maths Chapter 8 Exercise 8.4 Question 14.<\/strong>
\nIn a class of 35, students are numbered from 1 to 35. The ratio of boys to girls is 4:3. The roll numbers of students begin with boys and end with girls. Find the probability that a student selected is either a boy with a prime roll number or a girl with a composite roll number or an even roll number.
\nSolution:
\nn(S) = 35
\n\"10
\n\"Class<\/p>\n","protected":false},"excerpt":{"rendered":"

You can Download Samacheer Kalvi 10th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 8 Statistics and Probability Ex 8.4 10th Maths Exercise 8.4 Samacheer Kalvi Question 1. If P(A) = , P(B) = …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[2],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/168"}],"collection":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/comments?post=168"}],"version-history":[{"count":0,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/168\/revisions"}],"wp:attachment":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/media?parent=168"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/categories?post=168"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/tags?post=168"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}