{"id":1660,"date":"2023-11-19T05:06:24","date_gmt":"2023-11-18T23:36:24","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=1660"},"modified":"2023-11-20T16:54:55","modified_gmt":"2023-11-20T11:24:55","slug":"samacheer-kalvi-6th-maths-term-2-chapter-1-intext-questions","status":"publish","type":"post","link":"https:\/\/samacheerkalviguru.com\/samacheer-kalvi-6th-maths-term-2-chapter-1-intext-questions\/","title":{"rendered":"Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Intext Questions"},"content":{"rendered":"

You can Download Samacheer Kalvi 6th Maths Book Solutions<\/a> Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.
\n\"Samacheer<\/p>\n

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Intext Questions<\/h2>\n

Try These (Textbook Page No. 1)<\/span><\/p>\n

Question 1.
\n(i) Observe and complete:
\n1 + 3 = ?
\n5 + 11 = ?
\n21 + 47 = ?
\n___ + ____ = ?
\nFrom this observation, we conclude that \u201cthe sum of any two odd numbers is always an _____\u201d
\n(ii) Observe and complete:
\n5 \u00d7 3 = ?
\n7 \u00d7 9 = ?
\n11 \u00d7 13 = ?
\n_____ \u00d7 ____ = ?
\nFrom this observation, we conclude that \u201cthe product of any two odd numbers is always an _____\u201d
\nJustify the following statements with appropriate examples:
\n(iii) The sum of an odd number and an even number is always an odd number.
\n(iv) The product of an odd and an even number is always an even number.
\n(v) The product of only three odd numbers is always an odd number.
\nSolution:
\n(i) 1 + 3 = 4
\n5 + 11 = 16
\n21 + 47 = 68
\nAn odd number + another odd number = An Even number
\nFrom this observation, we conclude that the sum of any two odd numbers is always an even number.
\n(ii) 5 \u00d7 3 = 15
\n7 \u00d7 9 = 63
\n11 \u00d7 13 = 143
\nAn odd number \u00d7 Another odd number = An odd number
\nFrom this observation, we conclude that \u201cthe product of any two odd numbers is always an odd number.\u201d
\n(iii) Take the odd number 5 and the even number 10
\nTheir sum = 5 + 10 = 15, which is odd.
\n\u2234 Sum of an odd number and an even number is always an odd number.
\n(iv) Take the odd number 5 and the even number 10.
\nTheir product = 5 \u00d7 10 = 50, which is even
\nThus the product of an odd and an even number is always an even number.
\n(v) Consider 7 \u00d7 5 \u00d7 3
\nWe know that the product of any two odd numbers is an odd number
\n7 \u00d7 5 = 35, odd number.
\nAlso we have 35 \u00d7 3 = 105
\n\u2234 7 \u00d7 5 \u00d7 3 = 105, an odd number.
\nSo the product of three odd numbers is always an odd number.<\/p>\n

\"Samacheer<\/p>\n

Try These (Textbook Page No. 3)<\/span><\/p>\n

Question 1.
\n(i) Say True or False
\n(a) The smallest odd natural number is 1.
\n(b) 2 is the smallest even whole number.
\n(c) 12345 + 5063 is an odd number.
\n(d) Every number is a factor of itself.
\n(e) A number which is a multiple of 6 is also a multiple of 2 and 3.
\n(ii) Is 7, a factor of 27?
\n(iii) Is 12, a factor or a multiple of 12?
\n(iv) Is 30, a factor or a multiple of 10?
\n(v) Which of the following numbers has 3 as a factor?
\n(a) 8
\n(b) 10
\n(c) 12
\n(d) 14
\n(vi) The factors of 24 are 1, 2, 3, __, 6, ___, 12 and 24. Find the missing ones.
\n(vii) Look at the following numbers carefully and find the missing multiples.
\n\"Samacheer
\nSolution:
\n(i) (a) True
\n(b) False
\n(c) False
\n(d) True
\n(e) True
\n(ii) No, 7 is not a factor of 27. Because 7 does not divide 27 exactly
\n(iii) 12 is both a factor and a multiple of 12
\n(iv) 30 is a multiple of 10
\n(v) (a) Factors of 8 are 1, 2, 4, 8
\n(b) Factors of 10 are 1, 2, 5, 10
\n(c) Factors of 2 are 1, 2, 3, 4, 6, 12
\n(d) Factors of 14 are 1, 2, 7, 14
\n\u2234 The number 12 has 3 as a factor
\n(vi) Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.
\nMissing Factors 4, 8.
\n(vii) \"Samacheer<\/p>\n

Try These (Textbook Page No. 6)<\/span><\/p>\n

Question 1.
\nExpress 68 and 128 as the sum of two consecutive primes.
\nSolution:
\n68 = 31 + 37
\n128 = 61 + 67<\/p>\n

Question 2.
\nExpress 79 and 104 as the sum of any three odd primes.
\nSolution:
\n79 = 37 + 31 + 11
\n79 = 41 + 31 + 7
\n79 = 61 + 11 + 7
\n79 = 59 + 13 + 7
\n79 = 53 + 19 + 7 and so on.
\n104 cannot be expressed as the sum of three odd primes.
\nBecause we know that \u201c the sum of any two odd numbers is an even number\u201d.
\nAlso the sum of an odd and even number is always an odd number.
\n104 = 61 + 41 + 2
\n104 = 97 + 5 + 2
\n104 = 89 + 13 + 2 and so on.<\/p>\n

\"Samacheer<\/p>\n

Try These (Textbook Page No. 8)<\/span><\/p>\n

Question 1.
\nAre the leap years divisible by 2?
\nSolution:
\nLeap years are divisible by 4.
\nLeap years are divisible by 2.<\/p>\n

Question 2.
\nIs the first 4 digit number divisible by 3?
\nSolution:
\nThe first four-digit number is 1000.
\nSum of the digits is 1 + 0 + 0 + 0 = 1, not divisible by 3.
\n1000 is not divisible by 3.<\/p>\n

Question 3.
\nIs your date of birth (DDMMYYYY) divisible by 3?
\nSolution:
\nDate of birth 25.05.2007
\nSum of digits = 2 + 5 + 0 + 5 + 2 + 0 + 0 + 7 = 21
\nAgain 2 + 1 = 3, divisible by 3.
\nMy date of birth is divisible by 3.<\/p>\n

Question 4.
\nIdentify the numbers in the sequence 2000, 2006, 2010, 2015, 2019, 2025 that are divisible by both 2 and 5.
\nSolution:
\nWe know that a number is divisible by both 2 and 5 if it is divisible by 10. 2000 and 2010 are divisible by 10.<\/p>\n

Question 5.
\nCheck whether the sum of 5 consecutive numbers is divisible by 5.
\nSolution:
\nTake the first five consecutive natural numbers 1, 2, 3, 4 and 5.
\nTheir sum 1 + 2 + 3 + 4 + 5 = 15, divisible by 5.
\nAlso, 2 + 3 + 4 + 5 + 6 = 20, divisible by 5.
\n3 + 4 + 5 + 6 + 7 = 25, divisible by 5.
\nGenerally, the sum of 5 consecutive natural numbers is divisible by 5.<\/p>\n

Try These (Textbook Page No. 19)<\/span><\/p>\n

A small boy went to a town to sell a basket of wood apples. On the way, some robbers grabbed the fruits from him and ate them! The small boy went to the King and complained. The King asked him, \u201cHow many wood apples did you bring?\u201d. The boy replied, \u201cYour Majesty! I didn\u2019t know, but I knew that if you divided my fruits into groups of 2, one fruit would be left in the basket\u201d. He continued saying that if the fruits were divided into groups of 3, 4, 5 and 6, the fruits left in the basket would be 2, 3, 4 and 5 respectively. Also, if the fruits were divided into groups of 7, no fruit would be there in the basket. Can you find the number of fruits, the small boy had initially?
\n(This problem is taken from the famous Mathematics problems collection book in Tamil called \u201cKanakkathikaram\u201d under the heading of \u201cWood Apple Problem\u201d)
\nSolution:
\nThe total number of fruits, when divided by 2, 3, 4, 5 and 6, leaves the remainders 1, 2, 3, 4 and 5 respectively.
\nHere (2 – 1) = (3 – 2) = (4 – 3) = (5 – 4) = (6 – 5) = 1.
\n\u2234 The required no. of fruits will be LCM (2, 3, 4, 5, 6) – 1
\nL CM (2, 3, 4, 5, 6) = 2 \u00d7 3 \u00d7 2 \u00d7 5 = 60
\n\"Samacheer
\nNow take the multiples of 60 and subtract 1 from it.
\nAlso checking the conditions, multiplies of 60 are 60, 120, 180, …..
\nThe multiple -1
\n59, 119, 179, ……
\nThe required number = 119
\n\u2234 The total number of fruits = 119.<\/p>\n

\"Samacheer<\/p>\n","protected":false},"excerpt":{"rendered":"

You can Download Samacheer Kalvi 6th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Intext Questions Try These (Textbook Page No. 1) Question 1. (i) Observe and complete: 1 + …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[6],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/1660"}],"collection":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/comments?post=1660"}],"version-history":[{"count":1,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/1660\/revisions"}],"predecessor-version":[{"id":59957,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/posts\/1660\/revisions\/59957"}],"wp:attachment":[{"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/media?parent=1660"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/categories?post=1660"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalviguru.com\/wp-json\/wp\/v2\/tags?post=1660"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}