Category: Class 8

Students can Download Social Science Civics Term 3 Chapter 2 The Judiciary Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Social Science Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Social Science Civics Solutions Term 3 Chapter 2 The Judiciary

Samacheer Kalvi 8th Social Science Civics The Judiciary Textual Evaluation

I. Choose the best answer:

Question 1.
The highest and final judicial tribunal of India is-
(a) President
(b) Parliament
(c) Supreme Court
(d) Prime Minister
Answer:
(c) Supreme Court

Question 2.
Judicial system provides a mechanism for resolving disputes between-
(a) Citizen
(b) Citizen and the government
(c) Two State governments
(d) all the above
Answer:
(d) all the above

Question 3.
Dispute between States of India comes to the Supreme Court under-
(a) Original jurisdiction
(b) Appellate jurisdiction
(c) Advisory jurisdiction
(d) none of these
Answer:
(a) Original jurisdiction

Question 4.
Which of the following state/ Union territories have a common High Court?
(a) Punjab and Jammu Kashmir
(b) Assam and Bengal
(c) Panjab, Haryana and Chandigarh
(d) Uttar Pradesh and Bihar
Answer:
(c) Panjab, Haryana and Chandigarh

Question 5.
The System of Public Interest Litigation has been introduced in India by-
(a) Supreme Court
(b) Parliament
(c) Political parties
(d) Constitutional amendments
Answer:
(a) Supreme Court

Question 6.
How many courts are there in apex level in India?
(a) One
(b) Two
(c) Three
(d) Four
Ans:
(a) One

Question 7.
Supreme court is located at-
(a) Chandigarh
(b) Bombay
(c) Calcutta
(d) New Delhi
Answer:
(d) New Delhi

Question 8.
FIR means-
(a) First Information Report
(b) First information Result
(c) First Incident Report
(d) None of these
Answer:
(a) First Information Report

Question 9.
The court that hear criminal cases are called-
(a) District court
(b) Sessions court
(c) Family court
(d) Revenue court
Answer:
(b) Sessions court

II. Fill in the Blanks:

1. The ________High Court is the oldest High Court in India.
2. The framers of the Constitution established ________and _______ judiciary in India.
3. _______ a famous French philosopher propounded the idea of an independent judiciary.
4. ________ deals with disputes over money, property and social matters.
5. During ancient times, most of the Kings’ courts dispensed justice according to _______

Answer:

1. Calcutta
2. independent, impartial
3. Montesquieu
4. Civil Law
5. Dharmal

III. Match the following:

1. Supreme Court – social duties
2. High Court – speedy justice
3. Lok Adalat – highest court of appeal
4. Sir Elijah Impey – highest court in the States
5. Smiritis – chief justice

Answer:

1. Supreme Court – highest court of appeal
2. High Court – highest court in the States
3. Lok Adalat – speedy justice
4. Sir Elijah Impey – chief justice
5. Smiritis – social duties

IV. State True or False:

1. The Supreme Court of India was inaugurated on 28th January 1951.
2. During the Tughlaq period, the code of procedure was written in Arabic.
3. The Regulating Act of 1773 made provision for the formation of Supreme Court.
4. Sadar Diwani Adalat was a Criminal court of appeal.
5. The Allahabad High Court is the largest court in India.
6. The Constitution of India secures justice to all its citizen.

Answer:

1. False
2. True
3. True
4. False
5. True
6. True

V. Choose the correct statement:

Question 1.
Consider the following statements.

(i) A law commission was setup by Macaulay.
(ii) It codified the Indian Laws.

Which of the statements given above is / are correct?
(a) (i) only
(b) (ii) only
(c) Both (i) and (ii)
(d) Neither (i) nor (ii)
Answer:
(c) Both (i) and (ii)

Question 2.
Consider the following statements.

(i) An Indian Penal Code was prepared in 1860.
(ii) The Calcutta High Court was established in 1862.
(iii) The Government of India Act, 1935 created Federal Court.

Which of the statements given above is/are correct?
(a) (i) only
(b) (ii), (iii) only
(c) (i),(iii) only
(d) All the above
Answer:
(d) All the above

Question 3.
Which of the following statement is not true about India’s Supreme Court?
(i) The Supreme Court of India is the highest court of the land.
(ii) It was established by part V under Chapter IV of Indian Constitution.
(iii) Supreme court cannot transfer cases from one High court to another
(iv) Its decisions are binding on all courts
(a) (i)
(b) (ii)
(c) (iii)
(d) (iv)
Answer:
(c) iii

Question 4.
Assertion (A): The Supreme Court is a Court of Record.
Reason (R): It maintains records of the court proceedings and its decisions are finding upon the lower courts.
(a) A is correct and R is wrong.
(b) Both A and R are Wrong
(c) A is correct and R explains A
(d) A is correct and R does not explain A
Answer:
(c) A is correct and R explains A

Question 5.
Agree or disagree
(a) Every citizen of India can approach the Supreme court.
(b) Rich and powerful people control the judiciary system.
(c) Every citizen has a right to get justice through the courts.
(d) Politicians can not control over judges
Answer:
We agree with a, c, and d. Disagree with b

VI. Answer the following in one or two sentences:

Question 1.
Why do we need judicial system?
Answer:

1. Judiciary plays an important role as an organ of the government.
2. It administers justice, settles disputes, interprets laws, protects fundamental rights and acts as guardian of the Constitution.
3. So we need a judiciary to be efficient in order to ensure proper justice.

Question 2.
What are the different levels of courts in India?
Answer:
The different levels of courts in India are

1. Subordinate Courts.
2. District Courts.
3. High Court and
4. Supreme Court

Question 3.
Differentiate Law and Judiciary.
Answer:
Law:
It is a system of rules imposed through a government or institution to govern people.

Judiciary:
In law, the Judiciary or Judicial system is the system of courts which administers Justice in the name of the State.

Question 4.
Write a note on Lok Adalat.
Answer:

1. Lok Adalat was set up to provide speedy justice.
2. It hears and settles the disputes in the language of the people in the public presence.
3. A Lok Adalat is presided over by a retired judge along with a lawyer and a social worker.
4. Cases are put forward without advocates.
5. The first Lok Adalat was held on 1982 at Junagadh of Gujarat.

Question 5.
What are the advantages of mobile courts?
Answer:

1. Mobile courts will be of great relief to the rural people.
2. It would create greater awareness about the judicial system among the rural masses, cut costs for them and render justice at their doorstep.

VII. Answer the following in detail:

Question 1.
Write about the role of judiciary.
Answer:
Role of Judiciaiy can be classified as,
1. Dispute Resolution:
Role of Judiciary can be classified as, The Judicial system provides a mechanism for resolving disputes between Citizen, Citizens and the government, Two State governments,the Centre and the State governments

2. Judicial Review:
The Judicial has the power to declare a law unconstitutional if it believes that the law passed by the Parliament is violating the basic structure of the Constitution.

3. Upholding the Law and Enforcing Fundamental Rights:
Every citizen of India can approach the Supreme Court or High Court if they believe that their fundamental rights have been violated

Question 2.
Differentiate Civil Law and Criminal Law.
Answer:
Civil Law:

1. It deals with disputes over money property and social matters.
   Eg. Disputes relating to land, rent, marriage dispute etc.,
2. A petition has to be filed before the relevant court by the affected parties.
3. Sentences awarded in the form of money remuneration and as per the petitioner’s claim.

Criminal Law:

1. It deals with conducts or acts that the law defines as offences.
   Eg. Theft, murder, women harassment etc.,
2. It usually begins with lodging of an FIR (First Information Report) with police investigation after which a case is filed in the court.
3. Punishment is awarded if proven guilty, the accused is sent to jail.

Question 3.
Descrbe jurisdiction of Suppreme Court.
Answer:
1. Jurisdiction of Supreme Court:

• The Supreme Court can hear dispute for the first time in that court only.
• It is mainly concerned disputes between the Union and one or more states and between two or more states.

2. Appellate Jurisdiction:
It can hear appeals against the decisions made by the High Court on the granting of certificate by the High Court.

3. Advisory Jurisdiction: The Court can report to the President its opinion about a question of the public importance referred to it by the President.

4. Writs Jurisdiction:
The Writs are issued by the Supreme Court under Article 32 and by the High Courts under Article 226 of the Constitution of India.

5. Court of Record:
it maintains records of the court proceedings and its decisions are finding upon the lower courts.

6. Special Powers:
it supervises the functioning of the lower courts.

VIII. Project and Activity:

Question 1.
Discuss: Is it necessary to have an independent judiciary? List two reasons.
Answer:
Activity to be done by the students themselves

Question 2.
Organize your classroom for a lockup courtroom session. (Take a case with the help of the teacher)
Answer:
Activity to be done by the students themselves

Samacheer Kalvi 8th Social Science Civics The Judiciary Additional Questions

I. Choose the correct answer:

Question 1.
Supreme Court administers ………….
(a) justice
(b) settles disputes
(c) protects fundamental rights
(d) all of the abovel
Answer:
(d) all of the above

Question 2.
Fatawa – i – Alamgiri written in ………….
(a) 1670
(b) 1680
(c) 1660
(d) 1690
Answer:
(a) 1670

Question 3.
The East India Company established a Mayor’s Court in ………….
(a) Madras
(b) Bombay
(c) Calcutta
(d) All of the above
Answer:
(d) All of the above

Question 4.
Circuit Court was set up at ………….
(a) Calcutta
(b) Patna
(c) Dacca
(d) All of the above
Answer:
(d) All of the above

Question 5.
The cases dealing with land records are dealt with by ………….
(a) Sessions Court
(b) Panchayat Courts
(c) Revenue Courts
(d) LokAdalat
Answer:
(c) Revenue Courts

Question 6.
Fast Track courts were established in the year ………….
(a) 2000
(b) 1950
(c) 2010
(d) 1999
Answer:
(a) 2000Tele Law service is for the people in

Question 7.
Tele Law service is for the people in ………. areas.
(a) industrial
(b) rural
(c) Urban
(d) Coastal
Answer:
(b) rural

Question 8.
In 2005 these courts were established ………….
(a) Mobile courts
(b) Family Courts
(c) E – courts
(d) None of the above
Answer:
(c) E – courts

II. Fill In the blanks:

1. In ancient period Dharmic laws governed not only the individual but also the ………….
2. Amongst the Vajjis, there was a board of …………. Kulikas for the investigation of criminalcases.
3. A under the British a supreme court was established in 1824 in ………….
4. During the period of …………. four circuit courts were abolished.
5. The founding fathers of India constitution accorded highest place to ………….
6. Montesquieu was a …………. philosopher.
7. District courts hear …………. at the district level.
8. A Lok Adalat is presided over by a …………. along with a lawyer and a social worker.
9. The first Lok Adalat was held on 1982 at …………. of Gujarat.
10. The legal services authorities was passed in ………….
11. The special power of the Supreme Court is to supervises the functioning of the ………….
12. The Chief architect of the Indian constitution is …………..

Answer:

1. Society
2. eight
3. Bombay
4. William Bentinck
5. Justice
6. French
7. civil cases
8. retired judge
9. Junagadh
10. 1987
11. lower courts
12. Dr. B.R. Ambedkar

III. Match the following:

1. Ancient India – (a) Murshidabad
2. Fort William – (b) Law Commission
3. Circuit Court – (c) Weaker Sections
4. Macaulay – (d) Smiritis
5. NALSA – (e) Calcutta

Answer:

1. d
2. e
3. a
4. b
5. c

IV. State True or False:

1. Appeal proceeded from Gana Courts to Kula Courts
2. A supreme Court was established in Madras in 1801
3. Lord Cornwallis reorganised the civil and criminal judicial system.
4. Supreme Court can not transfer judges of High Courts.
5. The highest court of India is located in New Delhi.
6. An effective judiciary should be independent as well as accountable.

Answer:

1. False
2. True
3. True
4. False
5. True
6. True

V. Choose the correct Statement:

Question 1.
Consider the following Statements:

(i) A Supreme court was established for the first time at Fort Williams in Calcutta.
(ii) Sir Elijah Imphey was appointed its Chief Justice.

Which of the Statement/s given above is / are correct
(a) (i) only
(b) (ii) only
(c) Both (i) and (ii)
(d) Neither (i) nor (ii)
Answer:
(c) Both (i) and (ii)

Question 2.
Consider the following Statements:

(i) Family Courts specifically handle family law matters.
(ii) Mobile courts will be of great relief to the rural people.
(iii) The E-Court project was established in 2000 Which of the Statements given above is / are correct

(a) (i) only
(b) (i) and (ii) only
(c) (i) and (iii) only
(d) (iii) only
Answer:
(b) (i) and (ii) only

Question 3.
Which of the following statements is not true about different levels of courts in our country.

(i) Subordinate courts consider cases of civil and criminal nature.
(ii) District Courts can issue writs for restoring fundamental rights.
(iii) Supreme Court can transfer judges of High Court.
(iv) High Court can deal with cases within the jurisdiction of the state.

(a) (i)
(b) (ii)
(c) (iii)
(d) (iv)
Answer:
(b) (ii)

Question 4.
Assertion (A): Judiciary plays an important role as an organ of the government.
Reason (R): It administer justice, settles disputes, interprets laws protects fundamental rights.
(a) A is correct and R is wrong
(b) Both A and R are Wrong
(c) A is correct and R explains A
(d) A is correct and R does not explain A
Answer:
(c) A is correct and R explains A

VI. Answer the following in one or two sentences:

Question 1.
Who was Montesquieu?
Answer:

1. Montesquieu was the first political philosopher, who propounded the idea of an independent judiciary
2. He was famous French philosopher.
3. He believed in the theory of separation of powers of the three branches of the Government – Legislature, Executive and Judiciary.

Question 2.
What are Fast Track Court?
Answer:
Fast Track courts:
These courts were established in the year 2000 with an aim to clear the long pending Sessions and other lower judicial cases.

Question 3.
Explain the term Tele Law Initiative.
Answer:

1. To provide legal aid and service to the people in rural areas, the Tele Law Initiative was launched by the Ministry of Law and Justice in collaboration with the Ministry of Electronics and Information Technology.
2. People can seek legal advice from the lawyers through video conferencing available at the common service centre on the ‘Tele Law’ Portal.

Question 4.
Mention the role of Family Court.
Answer:

1. Family courts specifically handle family law matters.
2. They are civil courts and are utilised for various family related claims such as Child custody, Divorce, Adoption, Juvenile issues etc.,

Quetion 5.
State the importance of E- Courts?
Answer:

1. The E-Courts project was established in 2005.
2. According to the project all the courts will get computerised.
3. Judicial service centre is the part of e-court.
4. The public as well as the advocates can ask directly the case status and next hearing dates free of cost.

Question 6.
What is NALSA?
Answer:

1. The National Legal Service Authority has been constituted under the Legal Services Authorities Act, 1987 to provide free Legal Services to the weaker sections of the society.
2. It also organise Lok Adalats for amicable settlement of disputes.

Question 7.
Explain the term PIL.
Answer:

1. Public Interest Litigation (PIL):
   PIL is a litigation filed in a court of law for the protection of public interest.
2. The Supreme court introduced this šystem which allows a person to approach the court with his case.
3. PIL can be filed for the following reasons such as violation of basic human rights, religious rights, pollution, and road safety.
4. This could be done by a written letter stating the case. This concept is unique to the Indian Judiciary.

VII. Answer the following in detail:

Question 1.
Narrate the evolution of Indian Judiciary.
Answer:
1. Judiciary during ancient period:
During ancient times, the concept of justice was linked with religion. The king was regarded as the fountain head of Justice. Most of the Kings’ courts dispensed justice according to ‘dharma’, (righteousness and duty) a set of conventional laws, Dharmic laws governed not only the individual but also the society.

2. Judiciary during Medieval period:
The Tughlaq period saw the compilation of the code of civil procedure. It was called Fiqha-e-Feroze Shahi. The code prescribed details of the procedure and the law in several matters. It was written in Arabic and was translated into Persian.

3. Judiciary during Modern period:
(i) The Indian judicial system and laws we have today was formed by the British during the colonial rule in the country. The beginning of Indian codified common law is traced back to 1727 (Under the Charter of 1 726) when the Mayor ‘s court in Madras, Bombay and Calcutta were established by the East India Company.

(ii) Lord Cornwallis reorganised the civil and criminal judicial system. During tile period of William Bentinck four Circuit courts were abolished.

(iii) The Government of’ India Act 1935 created Federal Court.

Question 2.
Explain the Structure of Courts in India.
Answer:
There are three different levels of courts in our country.
1. Supreme Court of India:

• Its decisions are binding on all courts.
• Can transfer judges 6f High Courts.
• Can move cases from any courts to itself.
• Can transfer cases from one High Court to another.

2. High Court:

• Can hear appeals from lower courts.
• Can issue writs for restoring Fundamental Rights.
• Can deal with cases within the jurisdiction of the State.
• Exercises superintendence and control over courts below it.

3. District Court:

• Deals with cases arising in the District.
• Considers appeals on decisions given by lower courts.
• Decides cases involving serious criminal offences.

4. Subordinate Courts:

• Consider cases of civil and criminal nature.

Question 3.
Write a note on

1. District Court
2. Sessions Court
3. The Panchayat Courts
4. The Revenue Courts.

Answer:

1. District Courts – The Courts that hear civil cases at the district level are called District Courts.
2. Sessions Court – The Courts that hear criminal cases are called the Sessions Court.
3. The Panchayat Courts – The Panchayat Courts deal with Civil and Criminal cases at- the village level.
4. The Revenue courts – The Revenue courts deal with the cases of land records. It also assesses and collects land revenue from the land holders.

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Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 4 Information Processing Ex 4.2

Question 1.
Choose the correct answer

Question (i)
Common prime factors of 30 and 250 are
(a) 2 x 5
(b) 3 x 5
(c) 2 x 3 x 5
(d) 5 x 5
Answer:
(a) 2 x 5
Hint:
Prime factors of 30 are 2 x 3 x 5
Prime factors of 250 are 5 x 5 x 5 x 2
∴ Common prime factors are 2 x 5

Question (ii)
Common prime factors of 36, 60 and 72 are
(a) 2 x 2
(b) 2 x 3
(c) 3 x 3
(d) 3 x 2 x 2
Answer:
(d) 3 x 2 x 2
Hint:
Prime factors of 36 are 2 x 2 x 3 x 3
Prime factors of 60 are 2 x 2 x 3 x 5
Prime factors of 72 are 2 x 2 x 2 x 3 x 3
∴ Common prime factors are 2 x 2 x 3

Question (iii)
Two numbers are said to be co-prime numbers if their HCF is –
(a) 2
(b) 3
(c) 0
(d) 1
Answer:
(d) 1

Question 2.
Using repeated division method find HCF of the following:

1. 455 and 26
2. 392 and 256
3. 6765 and 610
4. 184, 230 and 276

1. 455 and 26 divisor
Solution:

• Step 1: The larger number should be dividend = 455 & smaller number should be divisor = 26
• Step 2: After 1st division, the remainder becomes new divisor & the previous divisor
• becomes next dividend.
• Step 3: This is done till remainder is zero.
• Step 4: The last divisor is the HCF

Answer:
The HCF is 13.

2. 392 and 256
256 is smaller, so it is the 1st divisor

∴ HCF = 8

3. 6765 and 610

∴ HCF = 5

4. 184, 230 and 276
First let us take 184 & 230

∴ 46 is the Hi of 184, and 230.
Now the HCF of the first two numbers is the dividend for the third number.

Answer:
HCF of 184, 230 & 276 is 46

Question 3.
Using repeated subtracting method find HCF of the following:

1. 42 and 70
2. 36 and 80
3. 280 and 420
4. 1014 and 654

1. 42 and 70
Solution:
Let number be m & n
m > n
We do m – n & the result of subtraction becomes new ‘m’. if m becomes less than n, we do n – m and then assign the result as n. We should do this till m = n. When m = n then ‘m’ is the HCF.
42 and 70 now m = 70, n = 42
70 – 42 = 28, now m = 42, n = 28
42 – 28 = 14, now m = 28, n = 14
28 – 14= 14, now m = 14, n = 14
we stop here as m = n
∴ HCF of 42 & 70 is 14

2. 36 and 80
Solution:
36 and 80 m = 80, n = 36
80 – 36 = 44, now n = 44, m = 36
Since n > m, we should do n m
44 – 36 = 8, now n = 8, m = 36
36 – 8 = 28
Similarly, processing, proceeding, we do repeated subtraction
till m = n
28 – 8 = 20
20 – 8 = 12
12 – 8 = 4
8 – 4 = 4 now m = n = 4
∴ HCF is 4

3. 280 and 420
Solution:
Let m = 420, n = 280
m – n = 420 – 280 = 140
now m = 280, n = 140
m – n = 280 – 140 = 140
now m = n = 140
∴ HCF is 140

4. 1014 and 654
Solution:
Let m = 1014, n = 654
m – n = 1014 – 654 = 360
now m = 654, n = 360
m – n = 654 – 360 = 294
now m = 360, n = 294
m – n = 360 – 294 = 66
now m = 294, n = 66
m – n = 294 – 66 = 228
now m = 66, n = 228
n – m = 228 – 66 = 162
now m = 162, n = 66
∴ m – n = 162 – 66 = 96
n – m = 96 – 66 = 30
Similarly 66 – 30 = 36
36 – 30 = 6
30 – 6 = 24
24 – 6 = 18
18 – 6 = 12
12 – 6 = 6
now m = n
∴ HCF of 1014 and 654 is 6

Question 4.
Do the given problems in repeated subtraction method
1. 56 and 12

2. 320,120 and 95

1. 56 and 12
Solution:
56 & 12
Let n = 56 & n = 12
m – n = 56 – 12 = 44
now m = 44, n = 12
m – n = 44 – 12 = 32
m – n = 32 – 12 = 20
m – n = 20 – 12 = 8
n – m = 12 = 8 = 4
m – n = 8 – 44. now m = n
HCF of 56 & 12 is 4

2. 320, 120 and 95
Let us take 320 & 120 first m = 320, n = 120
m – n = 320 – 120 = 200
m = 200, n = 120
∴ m – n = 200 – 120 = 80
120 – 80 = 40
80 – 40 = 40
∴ m = w = 40 → HCF of 320, 120
Now let us find HCF of 40 & 95
m = 95, n = 40
∴ m – n = 95 – 40 = 55
55 – 40 = 15
40 – 15 = 25
25 – 15 = 10
15 – 10 = 5
HCF of 40 & 95 is 5 10 – 5 = 5
HCF of 320, 120 & 95 is 5

Question 5.
On a school trip, 56 girls and 98 boys went to Kanyakumari. They were divided into as many groups as possible so that there were equal numbers of girls and boys in each group. Find the largest group possible? (To find the HCF using repeated division method)
Solution:
56 girls & 98 boys. Now, we need to find HCF of 56 & 98
Using repeated division method. So, we first divide. 98 by 56

Answer:
14.

Question 6.
Kalai wants to cut identical squares as big as she can, from a piece of paper measuring 168 mm and by 196 mm. What is the length of the side of the biggest square? (To find HCF using repeated subtraction method)
Solution:
Sides are 168 & 196
To find HCF of 168 & 196, we are to use repeated subtraction method.
m = 196, n = 168
m – n = 196 -168 = 28 now n = 28, m = 168
m – n = 168 – 28 = 140 now m = 140, n = = 28
m – n = 140 – 28 = 112 now m = 112, n = 28
m – n = 112 -28 = 84 now m = 84, n = 28
m – n = 84 – 28 = = 56 now m = 56, n = 28
m – n = 56 – 28 = 28
∴ HCF is 28
∴ Length of biggest square is 28

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Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 3 Geometry Ex 3.3

Question I.
Construct the following trapeziums with the given measures and also find their area.

Question 1.
AIMS with \(\overline { AI } \) ∥ \(\overline { SM } \), AI = 6 cm, IM = 5 cm, AM = 9 cm and MS 6.5 cm.
Solution:

Given
AI = 6cm
IM = 5cm
AM = 9cm, and \(\overline { AI } \) ∥ \(\overline { SM } \)
MS = 6.5 cm

Construction:
Steps:

1. Draw a line segment AI = 6cm.
2. With A and I as centres, draw arcs of radii 9 cm and 5 cm respectively and let them cut at M
3. Join AM and IM.
4. Draw MX parallel to AI
5. With M as centre, draw an arc of radius 6.5 cm cutting MX at S.
6. Join AS AIMS is the required trapezium.

Calculation of Area:
Area of the trapezium AIMS = \(\frac{1}{2}\) x h x (a + b) sq.units
= \(\frac{1}{2}\) x 4.6 x (6 + 6.5) = \(\frac{1}{2}\) x 4.6 x 12.5
= 28.75 Sq.cm

Question 2.
BIKE with \(\overline { BI } \) ∥ \(\overline { EK } \), BI = 4 cm, IK = 3.5 cm, BK = 6 cm and BE = 3.5 cm
Solution:

Given:
In the trapezium BIKE,
BI = 4 cm
IK = 3.5 cm
BK = 6 cm
BE = 3.5 cm and \(\overline { BI } \) ∥ \(\overline { EK } \)

Construction:
Steps:

1. Draw a line segment BI = 4 cm.
2. With B and I as centres, draw arcs of radii 6 cm and 3.5 cm respectively and let them cut at K.
3. Join BK and IK
4. Draw KX parallel to BI
5. With B as centre, draw an arc of radius 3.5 cm.cutting KX at E
6. Join BE. BIKE is the required trapezium.

Calculation of area:
Area of the trapezium BIKE = \(\frac{1}{2}\) x h x (a + b) sq. units = \(\frac{1}{2}\) x 3.5 x (4 + 4.2)
= \(\frac{1}{2}\) x 3.5 x 8.2 = 14.35 sq.cm

Question 3.
CUTE with \(\overline { CD } \) ∥ \(\overline { ET } \), CU = 7 cm, ∠UCE = 80°, CE = 6 cm and TE = 5 cm.
Solution:

Given:
In the trapezium CUTE,
CU = 7 cm, ∠UCE = 80°,
CE = 6 cm, TE = 5 cm and \(\overline { CD } \) ∥ \(\overline { ET } \)

Construction:
Steps:

1. Draw a line segment CU = 7 cm.
2. Construct an angle ∠UCE = 80° at C
3. With C as centre, draw an arc of radius 6 cm cutting CY at E
4. Draw EX parallel to CU
5. With E as centre, draw an arc of radius 5 cm cutting EX at T
6. 6. Join UT. CUTE is the required trapezium.

Calculation of area:
Area of the trapezium CUTE = \(\frac{1}{2}\) x h x (a + b) sq. units = \(\frac{1}{2}\) x 5.9 x (7 + 5) sq. units
= 35.4 sq.cm –

Question 4.
DUTY with \(\overline { DU } \) ∥ \(\overline { YT } \), DU = 8 cm, ∠DUT = 60°, UT = 6 cm and TY = 5 cm.
Solution:

Given:
In the trapezium DUTY
DU = 8 cm, ∠DUT = 60°,
UT = 6 cm, TY = 5 cm and \(\overline { DU } \) ∥ \(\overline { YT } \)

Construction:
Steps:

1. Draw a line segment DU = 8 cm.
2. Construct an angle ∠DUT = 60° at U
3. With U as centre, draw an arc of radius 6 cm cutting UA at T.
4. Draw TX parallel to DU
5. With T as centre, draw an arc of radius 5 cm cutting TX at Y
6. Join DE. DUTY is the required trapezium.

Calculation of area:
Area of the trapezium DUT Y = \(\frac{1}{2}\) x h x (a + b) sq. units= \(\frac{1}{2}\) x 5.2 x (8 + 5) sq. units = \(\frac{1}{2}\) x 5.2 x 13
= 33.8 sq.cm ,

Question 5.
ARMY with \(\overline { AR } \) ∥ \(\overline { YM } \), AR = 7 cm, RM = 6.5 cm ∠RAY = 100° and ∠ARM = 60° 5
Solution:

Given:
In the trapezium ARMY
AR = 7 cm, RM = 6.5 cm,
∠RAY = 100° and ARM = 60°, \(\overline { AR } \) ∥ \(\overline { YM } \)

Construction:
Steps:

1. Draw a line segment AR = 7 cm.
2. Construct an angle ∠RAX = 100° at A
3. Construct an angle ∠ARN = 60° at R
4. With R as centre, draw an arc of radius 6.5 cm cutting RN at M
5. Draw MY parallel to AR
6. ARMY is the required trapezium.

Calculation of area:
Area of the trapezium ARMY = \(\frac{1}{2}\) x h x (a + b) sq. units = \(\frac{1}{2}\) x 5.6 x (7 + 4.8) sq. units
= \(\frac{1}{2}\) x 5.6 x 11.8 = 33.04 sq.cm

Question 6.
BELT with \(\overline { BE } \) ∥ \(\overline { TL } \), BT = 7 cm ∠EBT = 85° and ∠BEL = 110°
Solution:

Given:
In the trapezium BELT
BE = 10 cm, BT = 7cm,
∠EBT = 85°, ∠BEL = 110° and \(\overline { BE } \) ∥ \(\overline { TL } \)

Construction:
Steps:

1. Draw a line segment BE = 10 cm.
2. Construct two angles ∠TBE = 85° and ∠BEL =110° respectively at the points B and E.
3. With B as centre, draw an arc of radius 7 cm cutting BX at T.
4. Draw TL ∥ BE
5. BELT is the required trapezium

Question 7.
CITY with \(\overline { CI } \) ∥ \(\overline { YT } \) Cl = 7 cm, IT = 5.5 cm, TY = 4 cm and YC = 6 cm.
Solution:

Given:
In the trapezium CITY,
Cl = 7 cm
IT = 5.5 cm
TY = 4 cm
YC = 6 cm, and \(\overline { CI } \) ∥ \(\overline { YT } \)

Construction:
Steps:

1. Draw a line segment Cl = 7 cm.
2. Mark a point D on Cl such that CD = 4cm
3. With D and I as centres, draw arcs of radii 6 cm and 5.5 cm respectively. Let them cut at T. Join DT and IT.
4. With C as centre, draw an arc of radius 6 cm.
5. Draw TY parallel to CL Let the line cut the previous arc at Y.
6. Join CY. CITY is the required trapezium.

Calculation of area:
Area of the trapezium CITY = \(\frac{1}{2}\) x h x (a + b) sq. units
= \(\frac{1}{2}\) x 5.5 x (7 + 4) sq. units = \(\frac{1}{2}\) x 5.5 x 11
= 30.25 sq.cm

Question 8.
DICE with \(\overline { DI } \) ∥ \(\overline { EC } \), DI = 6 cm, IC = ED = 5 cm and CE = 3 cm. Solution:

Given:
In the trapezium DICE,
DI = 6 cm
IC = ED = 5 cm
CE = 3 cm and \(\overline { DI } \) ∥ \(\overline { EC } \)

Construction:
Steps:

1. Draw a line segment DI = 6 cm.
2. Mark a point M on DI such that DM = 3cm
3. With D and I as centres, draw arcs of radii 5 cm each Let them cut at C. Join MC and IC.
4. Draw CX parallel to DI
5. With D as centre, draw an arc of radius 5 cm. Let it cut CX at E
6. Join DE. DICE is the required trapezium.

Calculation of area:
Area of the trapezium DICE = \(\frac{1}{2}\) x h x (a + b) sq. units = \(\frac{1}{2}\) x 3.8 x (6 + 3) sq. units
= \(\frac{1}{2}\) x 3.8 x 9 = 17.1 sq. cm

Students can Download Maths Chapter 5 Information Processing Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 5 Information Processing Additional Questions

Question 1.
Which one is the best buy of the following purchases. A pack of 5 soaps for ₹ 180 or 4 soaps for ₹ 128.
Solution:
From the pack, Cost of 5 soaps = ₹ 180
∴ Cost of 1 soap = \(\frac { 180 }{ 5 } \) = ₹ 36.
Also Cost of 4 soaps = ₹ 128
∴ Cost of 1 soap = \(\frac { 128 }{ 4 } \) = ₹ 32.
∴ Buying the pack of 5 is the best buy.

Students can Download Maths Chapter 5 Information Processing Ex 5.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 5 Information Processing Ex 5.2

I. Answer the following Questions

Question 1.
The sizes in MB, for nine computer files are given below. 53 82 61 38 23 41 16 34 42 The files are to be grouped into folders. Each folder may contain a maximum limit of 100 MB.
(a) Determine the minimum number of folders required.
(b) Use the first-fit method to group the files into folders.
(c) Use the first-fit decreasing method to group the files into folders.
Solution:
(a) Maximum number of folders required

(b) First fit method.

(c) First fit decreasing method.

Question 2.
A parcel delivery company has 4 motorcycles. Each motorcycle can carry a maximum load of 30kg. The weights of the parcels, (in kg), in the order they are waiting to be delivered are given below.

(a) Determine the minimum number of motorcycles required .
(b) Use the first-fit method to show how the parcels could be allocated to the motorcycles.
(c) Use the first-fit decreasing method to show how the parcels could be allocated to the motorcycles.
Answer:
(a) Minimum number of motorcycles required

(b) First fit method :

(c) First fit decreasing method :

Question 3.
A plumber wishes to cut the following sections from standard size of pipe each of length 6m.

Find the
(a) To cut according to the first-fit method calculate the wastage of the pipe length.
(b) To cut according to the first-fit decreasing method calculate the wastage of the pipe length,
Solution:
(a) First fit method :

(b) First fit decreasing method.

Students can Download Maths Chapter 5 Information Processing Ex 5.1 Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 5 Information Processing Ex 5.1

I. Choose the correct answer:

Question 1.
Online or television advertisements influence on spending decisions by
(a) using special music
(b) making me think I need the item
(c) using attractive pictures
(d) all the above
Answer:
(d) all the above

Question 2.
When I go shopping, I will buy
(a) something that looks attractive
(b) something my friend has
(c) something that I need to purchase
(d) the first thing I see in the store
Answer:
(c) something that I need to purchase

Question 3.
The best shopping choice is
(a) always shop at brand name stores
(b) compare the choices before buying
(c) the same thing my friends bought
(d) always buy at a regular shop
Answer:
(b) compare the choices before buying

II. Say true or false:

Question 1.
Wise consumers take time to compare two or three shops before spending money.
Answer:
True

Question 2.
Taking time to analyse advertisements cannot save money when shopping.
Answer:
False

Question 3.
One cannot shop on double and triple coupon discounts in available days.
Answer:
True

Question 4.
Every time one must make a shopping list and stick on within his/her budget.
Answer:
False

III. Find the best buy of the following purchases:

(i) A pack of 5 chocolate bars for ₹ 175 or 3 chocolate bars for ₹ 114?
(ii) Basker buy 1 1/2 dozen of eggs for ₹ 81 and Aruna buy 15 eggs for ₹ 64.5?
Solution:
(i)

Best buy is a pack of 5 chocolate bars for ₹ 175.

(ii)

Best buy is 15 eggs for ₹ 64.5

Question 4.
Using the given picture find the total special offer price of fresh sweets and bakery products to buy 1/2 kg laddu, 1 kg cake, 6 pockets of bread.

Solution:

Question 5.
Using given picture prepare a price list.
Suppose you plan to buy 1 1/2 kg of apple, 2 kg of pomegranate, 2 kg of banana, 3 kg of mango, 1/2 kg of papaya, 3 kg of onion, 1 1/2 kg of tomato, and 1 kg of carrot in shop 1, how much will you save compared to shop 2.

Solution:

Price in shop 2 – Shop 1 = 715 – 675.75 = ₹ 39.25
We can save ₹ 39.25 in shop 1 compared to shop 2.

Question 6.
When you plan to buy a shirt, one shop offers a discount of ₹ 200 on MRP ₹ 1000 and another shop offers 15% discount on the same MRP. Where would you buy?
Solution:
Price in I^st shop = ₹ 1000 – ₹ 200 = ₹ 800

Question 7.
Amazing park is offers a package deal of 5 entrance passes for ₹ 130. If one entrance pass normally costs ₹ 30, how much will you save by taking advantage of this special deal?
Solution:
Cost of one entrance pass = ₹ 30
∴ Cost of 5 entrance passes = 5 × 30 = ₹ 150
But special deal price = ₹ 130
Amount of saving = 150 – 130 = ₹ 20

Question 8.
Consider that you are going to buy the toys that are given below in the price list. Prepare a comparison price chart table and find where will you get the best offer price and also find how much you save?

[The amount to the nearest rupee as ₹ 789.84 is rounded off to ₹ 790]
Solution:

By shopping at Toys & Trades mart we can save ₹ 512 (4328 – 3816) then Golden toys in Toys & Trades mart we get the best price.

Students can Download Maths Chapter 4 Statistics Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Additional Questions

Question 1.
The following information shows the number of students opting different subjects in a college.

Draw a pie-chart to represent the information.
Solution:

Students opting different subjects.

Question 2.
The pie chart represents the expenditures of a family on different items. Find the percentage expenditures on different items by reading the pie-chart.

Solution:
Percentage value of the component =
∴ Percentage expenditures on various items are given as :

Question 3.
The following table gives the marks of 100 students represent in the form of a histogram.

Solution:
We take marks on X axis and frequency Y axis.

Students can Download Maths Chapter 4 Statistics Ex 4.3 Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.3

Miscellaneous and Practice Problems

Question 1.
Draw a pie chart for the given table.

Solution:
Converting the area in percentage into components parts of 360°, we have.

Question 2.
The data on modes of transport used by the students to come to school are given below. Draw a pie chart for the data.

Solution:
Converting the percentage into components parts of 360°, we have

Mode of Transport by students.

Question 3.
Draw a histogram for the given frequency distribution.

Solution:
The given distribution is discontinuous.
Lower boundary = lower limit — \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 41 – \(\frac { 1 }{ 2 } \) (1) = 40.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 45 + \(\frac { 1 }{ 2 } \) (1) = 45.5
Now continuous frequency table is as below

Question 4.
Draw a histogram and the frequency polygon in the same diagram to represent the following data.

Solution:
The given distribution is discontinuous.
Lower boundary = lower limit – \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 50 – \(\frac { 1 }{ 2 } \) (1) = 49.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 55 + \(\frac { 1 }{ 2 } \) (1) = 55.5
∴ The continuous frequency table is as below.

Question 5.
The daily income of men and women is given below, draw a separate histogram for men and women.

Solution:
The given data is continuous frequency distribution. So we take Income in X axis and No. of men in Y axis.

Now we consider the number of women and their income we have.

Challenging Problems

Question 1.
Form a continuous frequency distribution table and draw histogram from the following data.

Solution:
Converting into continuous distribution we have

Question 2.
A rupee spent in a cloth manufacturing company is distributed as follows. Represent this in a pie chart.

Solution:
1 Rupee = 100 paise.

Expenditure of a cloth manufacturing company.

Question 3.
Draw a histogram for the following data.

Solution:
Since mid values are given, the given distributors is discontinuous.
Lower boundary = lower limit — \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 15 – \(\frac { 1 }{ 2 } \) (10) = 10
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
15 + \(\frac { 1 }{ 2 } \) (10) = 20
The continuous distribution will be as follows.

Students can Download Maths Chapter 4 Statistics Ex 4.2 Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 4 Statistics Ex 4.2

Question 1.
Which of the following data can be represented in a histogram?

1. The number of mountain climbers in the age group 20 to 60.
2. Production of cycles in different years.
3. The number of students in each class of a school.
4. The number votes polled from 7 am to 6 pm in an election.
5. The wickets fallen from 1 over to 50th over in a one day cricket match.

Answers:

1. Yes
2. No
3. No
4. Yes
5. Yes

Question 2.
Fill in the blanks

1. The area of the rectangles are proportional to the _______ given.
2. The total area of the histogram is _______ to the total frequency of the given data.
3. _______ is a graphical representation of continuous frequency distribution with rectangles.
4. Histogram is a graphical representation of _______ data.

Answers:

1. frequency
2. proportional
3. Histogram
4. grouped

Question 3.
In a village, there are 570 people who have cell phones. An NGO survey their cell phone usage. Based on this survey a histogram is drawn. Answer the following questions.

(i) How many people use the cell phone for less than 3 hours?
Solution:
330 people (110+ 220)

(ii) How many of them use the cell phone for more than 5 hours?
Solution:
150 of them (100 + 50)

(iii) Are people using cell phone for less than 1 hour?
Solution:
No.

(iv) Give your suggestions on the data.
Solution:
People should minimise the usage of cell phones.

Question 4.
Draw a histogram for the following data.

Solution:
The given data is continuous frequency distribution taking class intervals on X axis and No. of students on Y-axis, the histogram is given below.

Question 5.
Construct a histogram from the following distribution of total marks of 40 students in a class.

Solution:
The given distribution is continuous taking marks on X axis and No. of students on Y-axis the histogram is constructed.

Question 6.
The distribution of heights (in cm) of 100 people is given below. Construct a histogram and the frequency polygon imposed on it.

Solution:
The given distribution is discontinuous.
Converting into continuous distribution we have
Lower boundary = lower limit – \(\frac { 1 }{ 2 } \) (gap between the adjacent class interval)
= 125 – \(\frac { 1 }{ 2 } \) (1) = 124.5
Upper boundary = Upper limit + \(\frac { 1 }{ 2 } \) (gap between adjacent class interval)
= 135 + \(\frac { 1 }{ 2 } \) = 135.5
∴ The new frequency table is

+

Question 7.
In a study of dental problem, the following data were obtained.

Represent the above data by a frequency polygon.
Solution:
Finding the midpoints of the class interval we get.

The points to be plotted are A (5,5), B (15, 13), C (25, 25), D (35, 14), E (45, 30), G (65, 43.), H (75, 50) to obtain the frequency polygon ZABCDEFGHI.
Where I imagined class between 80 and 90.

Question 8.
The marks obtained by 50 students in Mathematics are given below (i) Make a frequency distribution table taking a class size of 10 marks (ii) Draw a histogram and a frequency polygon.

Solution:
Maximum marks obtained = 89
Minimum marks obtained = 08
Range = Maximum marks – Minimum marks = 89 – 08 = 81
Taking the class size = 10, then

Now we have the continuous frequency table.

We will draw the histogram taking class interval in x axis and frequency in y axis as follows.

Objective Type Questions

Question 1.
Data is a collection of _______
(a) numbers
(b) words
(c) measurements
(d) all the three
Answer:
(d) all the three

Question 2.
The number of times an observation occurs in the given data is called _______
(a) tally marks
(b) data
(c) frequency
(d) none of these
Answer:
(c) frequency

Question 3.
The difference between the largest value and the smallest value of the given data is _______
(a) range
(b) frequency
(c) variable
(d) none of these
Answer:
(a) range

Question 4.
The data that can take values between a certain range is called _______
(a) ungrouped
(b) grouped
(c) frequency
(d) none of these
Answer:
(b) grouped

Question 5.
Inclusive series is a _______ series
(a) continuous
(b) discontinuous
(c) both
(d) none of these
Answer:
(b) discontinuous

Question 6.
In a class interval the upper limit of one class is the lower limit of the other class. This is _______ series.
(a) Inclusive
(b) exclusive
(c) ungrouped
(d) none of these
Answer:
(b) exclusive

Question 7.
The graphical representation of un grouped data is _______
(a) histogram
(b) frequency polygon
(c) pie chart
(d) all the three

Question 8.
Histogram is a graph of a _______ frequency distribution.
(a) continuous
(b) discontinuous
(c) discrete
(d) none of these
Answer:
(a) continuous

Question 9.
A _______ is a line graph for the graphical representation of the continuous frequency distribution.
(a) frequency polygon
(b) histogram
(c) pie chart
(d) bar graph
Answer:
(a) frequency polygon

Question 10.
The graphical representation of grouped data is _______
(a) bar graph
(b) pictograph
(c) pie chart
(d) histogram
Answer:
(d) histogram

Students can Download Maths Chapter 5 Information Processing Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 8th Maths Solutions Term 3 Chapter 5 Information Processing Intext Questions

Exercise 5.1
Activity 1 (Text book Page No. 104)

Question 1.
Consider that you are going to a store with your total budget of ₹ 220 to buy things without changing the quantity of the items given in the list below with the following conditions.

Conditions :
(i) First you have to complete the price list given.
(ii) You have to buy three items as per the given price list but within your budget ₹ 220.
(iii) You won’t carry exceeding 5kg because you have to walk home carrying them, so they cannot be bulky.

Now, answer the following questions:
1. In how many ways can you buy your items? Complete the price lists given below. One is done for you.
2. Which one is the best purchase price list and why?

Answer:

Try this (Text book Page No. 106)

The teacher divides the class into four groups and setup a mock market in the class room and ask the students to involve in role play as two groups of businessmen and two groups of consumers. Consumers have to buy products at different shops and prepare a price list.

The two supermarkets in which the two groups buy are Star Food Mart and Super Provisions. Th is week they each have got a special deal on some products. At Star Food Mart, you can buy items at discount prices. At Super Provisions, there are some “BUY ONE GET ONE” deals. Flave a look at their deal:

Now, answer the following questions.

I. Here is your shopping list:
4 bottles of Protein Milk (200 ml size), 2 packets of Peanut candies(200 gm), 1 packet of Chocolate biscuits and 1 packet of Badam nuts (500 gm)
(i) If you buy all the items in one shop, where will you get the best price?
(ii) If you buy the items from different shops, how will you do it to spend the least amount of money?

II. You have ₹ 1000/- to spend to buy the following shopping list:
6 bottles of Protein Milk (200 ml size), 3 packets of Peanut candies (200 gm), 3 packets of Chocolate biscuits and 1 packet of Badam nuts (250 gm).

(i) How can you do this so that you don’t go over your budget amount ₹ 1000?
(ii) Which shop offers you the best value for money on each item?
(iii) Is the “BUY ONE GET ONE” deal at Super Provisions the same as “50% off’ deal?
Solution:
Prices of Star Food Mart.


(i) In star Food Mart
(ii) Badam nuts from super provisions and other items from Star Food Mart.

II. Comparing two stores.

(i) We can buy them from any one shop.
(ii) Star Food Mart.
(iii) Yes

Exercise 5.2
Try this (Text book Page No. 117)

Question 1.
If Kumaran cut the woods using first fit method then find the wastage pieces.
Solution:

Waste pieces = 2 feet + 4 feet + 2 feet = 8 feet

Activity 1 (Text book Page No. 117)

Question 1.
Seva Sangam has decided to deliver some aids to flood victims via lorries with a maximum capacity of 5000kg. All of these items that are given below are to be packed and sent in the lorry.

Solution: